Question

64÷4 to the 2nd power x 3 to the 2nd power +2 to tbe 3rd power =?

Please help me

Answer 1

Please print in standard notation. Is this what you mean?

64 + (4^2 * 3^2)+ 2^3 = 64 + (16*9) + 8 = ?

Answer 2

if you're asking about math, use math notation. Your words are ambiguous

64÷4^2 * 3^2 + 2^3 = 64÷16 * 9 + 8 = 4*9+8 = 44

64÷(4^2 * 3^2) + 2^3 = 64/36 + 8 = 16/9 + 8 = 9 7/9

64÷4^2 * (3^2 + 2^3) = 16*13 = 208

use parens to make it clear just what you mean.

Answer 3

[AI-generated answer — Explain Bot]

To get the answer to this expression, we need to follow the order of operations, which is also known as PEMDAS (Parentheses, Exponents, Multiplication and Division from left to right, Addition and Subtraction from left to right).

Let's break down the problem step by step:

1. 64 ÷ 4 = 16
We divide 64 by 4, which equals 16.

2. Next, we have to calculate the exponents:
16^2 = 16 * 16 = 256
We square 16, which is equivalent to multiplying it by itself, resulting in 256.

3^2 = 3 * 3 = 9
We square 3, which is equivalent to multiplying it by itself, resulting in 9.

2^3 = 2 * 2 * 2 = 8
We cube 2, which is equivalent to multiplying it by itself twice, resulting in 8.

3. Now, let's substitute the calculated values into the expression:
256 * 9 + 8

4. Perform the multiplication first:
256 * 9 = 2304

5. Finally, add the result of the multiplication with the third power of 2:
2304 + 8 = 2312

Therefore, the value of the expression 64 ÷ 4 to the 2nd power x 3 to the 2nd power + 2 to the 3rd power is 2312.