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6/(√3+2) = 6(√3-2)/-1 = 12-6√3
or, B
or, B
First, let's simplify the expression inside the square root. The sum of 3+2 is 5.
So, the expression becomes 6 over the square root of 5.
To simplify the square root of 5, we need to rationalize the denominator by multiplying the expression by its conjugate. The conjugate of the square root of 5 is the negative square root of 5.
Thus, we can multiply both the numerator and denominator by the conjugate to get:
(6/1) * (√5/√5) = 6√5/5.
So, the simplified form of 6 over the square root of (3+2) is 6√5/5.
Let me know if you have any other questions!