since you have 3u^2, look for multiples of 3:
3u^2-21u = 3u(u-7)
Work on that idea. But why both the -7 and +49 constant terms?
Looks like a typo to me.
3u^2-7-21u+49
Would be the same procedure as factoring polynomial?
Thanks!
3u^2-21u = 3u(u-7)
Work on that idea. But why both the -7 and +49 constant terms?
Looks like a typo to me.
I am so confused!
3u^2-21u+42
and that does not factor.
I am unsure of what the answer is.
Better check with your teacher.
Thanks!
To factor the given expression, 3u^2 - 7 - 21u + 49, we will use factoring by grouping. Here's how to do it:
Step 1: Group the terms in pairs.
(3u^2 - 7) - (21u - 49)
Step 2: Factor out the greatest common factor from each group.
The first group has a common factor of 1, and the second group has a common factor of -7.
1(3u^2 - 7) - 7(3u - 7)
Step 3: Now, check if you can factor out a common binomial factor from the two grouped terms.
In this case, we notice that (3u - 7) is the common factor.
Therefore, we can factor out (3u - 7) from both terms:
(3u - 7)(u + 1) - 7(3u - 7)
Step 4: Check that both expressions inside the parentheses are the same.
Since both expressions are (3u - 7), we can now factor out the common binomial factor:
(3u - 7)(u + 1 - 7)
Simplifying the resulting expression, we have:
(3u - 7)(u - 6)
So, the factored form of the polynomial 3u^2 - 7 - 21u + 49 is (3u - 7)(u - 6).