Question

50 Ltr. Of a certain liquid is confined in a piston system at the extenal pressure 100 atm this pressure suddenly released and liquid is expanded against a contant atm pressure , vol. Of liquid increases by 1 Ltr and the final pressure of the liquid is 10 atm. Find the work done.

Answer 1

1L.atm

Answer 2

4600J i.e 1lit.atm

Here p and v both are change
Delta(pv) apply here and get solution

Answer 3

[AI-generated answer — Step-by-Step Bot]

To find the work done during the expansion of the liquid, we can use the formula for work done by a gas:

Work = Pressure * Change in Volume

Given:
Initial volume of the liquid, V1 = 50 L
External pressure, P1 = 100 atm
Change in volume, ΔV = 1 L
Final pressure of the liquid, P2 = 10 atm

We need to calculate the work done during the expansion, so let's substitute the values into the formula:

Work = (P1 - P2) * ΔV

Work = (100 atm - 10 atm) * 1 L

Work = 90 atm * 1 L

Since atm is a unit of pressure, and work is typically expressed in units of energy, we need to convert atm to a unit of energy called joules (J).

To do this, we need to know the conversion factor between atm and J. The conversion factor is:

1 atm = 101.325 J

Multiplying the work by the conversion factor, we get:

Work = 90 atm * 1 L * 101.325 J/atm

Work = 9092.25 J

So, the work done during the expansion of the liquid is 9092.25 joules.

Answer 4

[AI-generated answer — Explain Bot]

To find the work done in this scenario, we can use the formula:

Work = Pressure * Change in Volume

First, let's calculate the change in volume. We are given that the volume of the liquid increases by 1 liter.

Change in Volume = 1 L - 0 L (initial volume)

Now, we can calculate the work done:

Work = Pressure * Change in Volume

We have the initial pressure as 100 atm and the final pressure as 10 atm.

Work = (100 atm - 10 atm) * 1 L

Simplifying, we get:

Work = 90 atm * 1 L

Since we cannot multiply different units, we need to convert atm * L to a common unit. The unit for work is usually joules (J), so we can convert atm * L to joules.

1 atm = 101.325 J (approximately)
1 L = 0.001 m^3

Therefore,

Work = 90 atm * 1 L * 101.325 J/atm * 0.001 m^3/L

Work = 9,132.15 J

So, the work done in this scenario is approximately 9,132.15 joules.