[ a+b ]/2 = 81
so
a+b = 162
but b = a+26
so
2 a + 26 = 162
2 a = 136
a = 68
The average of two numbers is 81. The difference between the number is 26. What is the smaller number?
so
a+b = 162
but b = a+26
so
2 a + 26 = 162
2 a = 136
a = 68
Let's assume the smaller number as 'x' and the larger number as 'y'.
From the given information, we know that the average of the two numbers is 81:
(x + y) / 2 = 81
We also know that the difference between the numbers is 26:
y - x = 26
Now, we can solve this system of equations to find the values of x and y.
First, we can rearrange the second equation to solve for y:
y = x + 26
Now, substitute this value of y in the first equation:
(x + (x + 26)) / 2 = 81
Simplifying further:
(2x + 26) / 2 = 81
Canceling out the denominator:
2x + 26 = 162
Subtracting 26 from both sides:
2x = 162 - 26
2x = 136
Dividing both sides by 2:
x = 68
So, the smaller number (x) is 68.