A calculator manufacturing company checks 500 calculator units, and 25 of them have non-functioning keys. Approximate the relative frequency of a non-defective unit from this batch of items. Express your answer in the simplest form of a fraction.(1 point)
Responses
25500
Start Fraction 25 over 500 End Fraction
475500
Start Fraction 475 over 500 End Fraction
1920
Start Fraction 19 over 20 End Fraction
120
its 19 over 20
Yes, that is correct. The relative frequency of a non-defective unit is 19/20.
Start Fraction 475 over 500 End Fraction = Start Fraction 19 over 20 End Fraction
x/(x+2)/((1/x)+1/(x+2))
A: x^2/2
B: x^2/x+2
C: x^2/2x+2
D: x^2+2x+2/2x+2
We can simplify the expression as follows:
x / (x + 2) / ((1/x) + (1/(x + 2)))
= x / (x + 2) / ((x + (x + 2)) / (x(x + 2))) [Taking LCM and simplifying fractions]
= x * x(x + 2) / (x + 2) * (2x + 2) [Dividing by a fraction is equivalent to multiplying by its reciprocal]
= x^2 / (2x + 2)
= x^2 / 2(x + 1)
Therefore, the answer is (C) x^2/2x+2.
Start Fraction 475 over 500 End Fraction
To approximate the relative frequency of a non-defective unit from this batch of items, we need to calculate the fraction of non-defective units out of the total number of units checked.
First, we need to find the number of non-defective units. Since there are 25 defective units out of 500 checked, we can subtract the number of defective units from the total number of units checked to get the number of non-defective units:
Non-defective units = Total units checked - Defective units
Non-defective units = 500 - 25
Non-defective units = 475
Now, we can express the relative frequency of non-defective units as a fraction:
Relative Frequency = Number of non-defective units / Total units checked
Relative Frequency = 475 / 500
To simplify the fraction, we can divide both the numerator and denominator by their greatest common divisor, which is 25:
Relative Frequency = 19 / 20
Therefore, the relative frequency of a non-defective unit from this batch of items is Start Fraction 19 over 20 End Fraction.