d/dx ∫(2x, 0) cot(t^5)dt
898 results
Justin wants to evaluate 3cot(5pi/4). Which of the following identities can he use to help him? Select two answers.
cot(theta) = cot(theta) cot(theta) = cot(theta) cot(theta) = cot(theta) cot(theta + pi) = cot(theta) cot(theta + 2pi) = cot(theta)

1)if the graph of f(x)=cotx is transformed by a horizontal shrink of 1/4 and a horizontal shift left pi, the result is the graph of:
a) g(x)= cot[1/4(xpi)] b) g(x)=cot[1/4(x+pi)] c) g(x)=cot[4(xpi)] d) g(x)=cot[4(x+pi)] e) g(x)=cot[4x+pi] please include

A right triangle has acute angles C and D. If tan C=158 and cos D=1517, what are cot D and sin C?
cot D=8/15 and sin C=8/17 cot D=8/15 and sin C=15/17 cot D=15/8 and sin C=15/17 cot D=15/8 and sin C=8/17

All right, sorta hard to explain but I will try my best. I am suppose to find the equation for the that lines that are tangent to the curve y=cot^2(x) at the point (pie/4, 1)....(the x is not to the power of 2, a variable right next to the cot^2)
I am not

I am having trouble with this problem.
sec^2(pi/2x)1= cot ^2x I got : By cofunction identity sec(90 degrees  x) = csc x secx csc1 = cot^2x Then split sec x and csc1 into two fractions and multiplied both numerator and denominators by csc and got: sec x

Algebraically find the value of: 10 cot(cot^(1)3+cot^(1)7+cot^(1)13+cot^(1)21 )

Hello,
I'm having trouble with this exercise. Can you help me? Integral of (x* (csc x)^2)dx I'm using the uv  integral v du formula. I tried with u= (csc x)^2 and used some trigonometric formulas, but the expression became too complicated, I couldn't

Use implicit differentiation to show
dy/dx = [(1xy)cot(y)]/[x^2 cot(y) + xcsc^2(y)] if xy = ln(x cot y).

verify (csc^41)/cot^2x=2+cot^2x
So this is what I have so far on the left side (csc^2x+1)(cscx+1)(cscx1)/cot^2x =(csc^2x+1)(cot^2x)/cot^2x i think I'm doing something wrong. Please help!

use the quotient and reciprocal identities to simplify the given expression
cot t sin t csc t sin t tan t cot t cot t sec t

Simplify (cos x)/(sec(x) + 1)
a. cot^2 x  cot^2 x * cos x b. cot^2 x + cot^2 x * cos x c. cos^2 x + cos x d. cot^2 x  cot^2 x * sin x

Please review and tell me if i did something wrong.
Find the following functions correct to five decimal places: a. sin 22degrees 43' b. cos 44degrees 56' c. sin 49degrees 17' d. tan 11degrees 37' e. sin 79degrees 23'30' f. cot 19degrees 0' 25'' g. tan

Verify the identity.
(csc(2x)  sin(2x))/cot(2x)=cos(2x) =csc(2x)/cot(2x)  sin(2x)/cot(2x) =csc(2x)/cot(2x)  cos(2x) Is this correct so far? If so then how would I continue? I got stuck on this part...

Factorthen use fundamental identities to simplify the expression below and determine which of the following is not equivalent cot^2 a * tan^2 a + cot^2 a A. csc^ 2 alpha B.1/ sin^ 2 alpha C.1/ 1cos^ 2 alpha D.sec^ 2 alpha E.1+cot^ 2 alpha

What is the first step. Explain please.
Which expression is equivalent to cos^2x + cot^2x + sin2^x? a) 2csc^2x b) tan^2x c) cot^2x d) csc^2x cos^2x + cot^2x + sin2^x

how do I simplify these?
1. (Cot/1tan) + (Tan/1Cot)  Tan  Cot 2. (1+cos) (csccot)

Find cot x if sin x cot x csc x = .square root 2
After reducing i got cot= square root of 2 Am i correct?

Hi everyone :)
I need a lot of help. I have many questions i don't get how to do and even if you can help me with one of them, I'd truly appreciate it. I really need the help and i gotta hand this in soon so please help if you know how to do any of these

Prove:
Cot x cot 2x  cot 2x cot 3x  cot 3x cot x = 1

if sina,cosa,tana are in geometric progression then prove that cot^6acot^2a=1

Express the function in the form
f compose g. (Use nonidentity functions for f and g.) u(t) = cot t/(9+cot t) {f(t), g(t)}=?

HELP!!!! I don't know how to do the trig identity with this problem
csc^4 xcot^4x= Csx^2 x + cot^2x

prove the identity
sec^2x times cot x minus cot x = tan x

if sina, cosa, tana are in geometric progression then prove that cot^6acot^2a=1

Factor; then use fundamental identities to simplify the expression below and determine which of the following is not equivalent cot^2 a * tan^2 x + cot^2 a

given cotA square root of 5, find cotB at the 4th quadrant.

Find all angles between 0 and 2 phi inclusive which satisfy
cot 2z = 1 + cot z

sin^2 x + cos^2 x = 1
using that, derive what the cot^2 x would equal to. would it be csc^2 x  1 = cot^2 x

If sinA=12/13 & tan B=3/4 then find
¡= sin(A+B) ¡¡=COS(AB) ¡¡¡=COT(AB) ¡v=cot(AB) Sir please give me the correct ans because tomorrow is my class

If 2tanA+cot A=tan B, then prove that 2tan(BA)=cot A

Factor the trigonometric expression. There is more than one correct form of the answer.
cot^2 x + csc x − 19 NOT SURE WHETHER TO REPLACE THE COT WITH COS^2X/SIN^2X THEN CSCX TO 1/SINX?

I'm trying to verify these trigonometric identities.
1. 1 / [sec(x) * tan(x)] = csc(x)  sin(x) 2. csc(x)  sin(x) = cos(x) * cot(x) 3. 1/tan(x) + 1/cot(x) = tan(x) + cot(x) 4. csc(x)/sec(x) = cot(x)

How do you simplify these equations:
1.)(2/cot^3(x)  cot^2 (x)) + (2/cot (x)2) 2.) (2/ tan^2 (x)) + (2/ tan(x) 2)

Find all solutions of θ in radians where (0 ≤ θ < 2π) given: 1+cot^2xcot^4x=1

Verify:
tan^2a=cot^2acot^2acsc^2a

d/dx (cot(x) / sin(x)) =
I got dy/dx= csc(x)  cos(x)cot(x)

Verify the identity algebraically.
TAN X + COT Y/TAN X COT Y= TAN Y + COT X

Simplify the trigonometric function
sin^4xcos^4x cos^2âsin^2â=1+2cosâ (1+cot^2x )(cos^2x )=cot^2x cot^2t/csct =(1sin^2t)/sint (Work on both sides!) sinècscè sin^2è=cos^2è

For each expression in column I, choose the expression from column II to complete an identity:
Column I Column II 1. tanxcosx A. sin^2x/cos^2x 2. sec^2x1 B. 1/sec^2x 3. sec x/cscx C. sin(x) 4. 1+sin^2x D.csc^2xcot^2x+sin^2x 5. cos^2 x E. tanx I figured

Can someone please help me do this problem? That would be great!
Simplify the expression: sin theta + cos theta * cot theta I'll use A for theta. Cot A = sin A / cos A Therefore: sin A + (cos A * sin A / cos A) = sin A + sin A = 2 sin A I hope this will

Hello
lim x>pi^ for cot(x) [In words,this is the limit of x as it approaches pi from the negative direction for the function cot(x). I am very confused as to how this occurs and turns out to be negative infinity. Thanks.]

How do we find what "a" is equal to?
I am not sure if we are supposed to put it back to tangent and then find the common denominator? Please help!?!? a cot 16  a cot 57 = 9.167

I posted this question before at 7:14
I think the answer to it is 0. cot(40)  ((sin(50))/(sin(40)) = ? these are also degrees steps too please. I thought since 50+40= 90 then that part would be 1, but then how would cot 40 turn out to be 1

integral of cscx^(2/3)(cot^3)x
i know that cot^2x is csc^2(x)1, but i just don't understand how to solve the cscx^(2/3), any help? i also know that its trig integrals/substitution...

Find the values of the trigonometric function cot 8/17
sin: sec: tan: cot: I know you use a Pythagorean Identity, sin^2t + cos^2t=1 I got 64/289 for the first one for example and it was wrong.

Are these correct?
5. is sin θ = 7/13 and cos θ = 12/13, find tan θ and cot θ using Quotient Identities. answers: tan (θ) = (7/12) cot (θ) = (12/7)

So I have a math problem where I need to solve an equation for x where x is within (0, 2pi)
I have it simplified down to cotx+cot^2x=0 and cotxcot^2x=0 but I don't know where to go from here

Differentiate.
y= u(a cos u + b cot u) I am not sure if this correct. I was not sure whether to leave the variables as are or where the negatives should be placed? (u)*( a sin u  b csc^2 u) + (a cos u + b cot u)*(1)

Prove cot u  cot 2u=cosec 2u?

How do you solve 6[cot(2pi/3)cot(pi/3)]?

prove cot x tan x = 2 cot 2x

Prove cot^2x/cot^2x+1=cos^2x

let x+y=tan y. show that y"=2[cot^5y+cot^3y]

simplify (1cot^2x sec^2x) / ( cot^2x)

simplify (1cot^2x sec^2x) / ( cot^2x)

I don't think its right . can you correct me please .
A.log sin A = 9.91655  10 sinA = 0.82537 A = 55.626° = 55° 34' 35" B.log cot A = 0.11975 cot(A) = 1.317498... A = 37.199 degs A = 37º 11' 56"

I don't think its right . can you correct me please .
A.log sin A = 9.91655  10 sinA = 0.82537 A = 55.626° = 55° 34' 35" B.log cot A = 0.11975 cot(A) = 1.317498... A = 37.199 degs A = 37º 11' 56"

Cot 495 degrees... a) tan 135 degrees
b) cot 135 degrees c) cot 135 degrees d) cot 315 degrees

Hello all,
In our math class, we are practicing the trigonometric identities (i.e., sin^2(x)+cos^2(x)=1 or cot(x)=cos(x)/sin(x). Now, we are working on proofs that two sides of an equation are equal (for example, sin(x)*csc(x)=1;

how do you veriy
tan x + Cot y  = tan y + cot x 1tan x cot y sin^4x + cos^4x = 1 2cos^2x + 2cos^4

How would I evaluate these trig functions without using a calculator? U:
sin(13π/6) cot 11π/6 cot(14π/4) sec 23π/6 Thanks in advance ^^; and if you'd tell me step by step on how to do problems like these I'd be grateful :D

Without using tables, evaluate:
(4 tan 60° sec 30° ) + [(sin 31 sec 59° + cot 59° cot 31°)/ (8 sin² 30°tan² 45°)]

Prove the following identity:
(i) tan^3x/1+tan^2x + cot^3x/1+cot^2 = 12sin^x cos^x/sinx cosx

prove (tan^3x/1 tan^2x) (cot^3x/1 cot^2) = (12sin^2x cos^2x)/sinx cosx

Simplify the follow)ing to the simplest form
(tan(x) +cot(x))/ (tan(x)*cot(x))

Find the derivative of
y=cot³(12x)² y'=3[cot(12x)²]² (csc²(12x)²)(24x)(2) y'=(6+24x)[cot(12x)²]²(csc²(12x)²) How do you simplify further?

If A+B+C=180 and sin a= sin b sin c prove that
cot a= 1 cot b cot c

Julia wants to simplify the term sec^2 theta1/cot^2 theta+1 in a trigonometric identity that she is proving. Which of the following identities should use to help her? Select all that apply. (2 ANSWERS)
a. sin^2 theta+cos^2 theta=1 b. sec^2 thetatan^2

Solve and prove the identity
(tan x+ cot (x))/ (tan x  cot(x))= 12cos^2(x)

Use the given information to evaluate cos (ab).
Cot a = 3/4, cot b = 24/25; pi<a<3pi/2, 3pi/2<b<2pi.

Find the values of the six trigonometric functions of θ. (If an answer is undefined, enter UNDEFINED.)
Function Value: csc(θ) = 4 Constraint: cot(θ) < 0 1) sin(θ)= 2) cos(θ)= 3) tan(θ)= 4) csc(θ)= 5) sec(θ)= 6) cot(θ)=

Prove:
sin^2(x/2) = csc^2x  cot^2x / 2csc^2(x) + 2csc(x)cot(x) On the right, factor the numberator as a difference of two perfect squares. In the denominator, factor out 2cscx. You ought to prodeed rather quickly to the proof.

For all values x for which the terms are defined, fidnteh value(s) of k, 0<k<1, such that
cot(x/4)  cot(x) = [sin(kx)]/[sin(x/4)sin(x)] PLEASEEEE HELP! ASAP!

Determine the values of sin, cos, tan, csc, sec and cot at (3, 3) on the terminal arm of an angle in standard position
2. If cos θ = 2/3 and 270° < θ < 360° then determine the exact value of 1/cot

Find the complete solution of each equation. Express your answer in degrees.
sec^2 θ+sec θ=0 2 cos^2 θ+1=0 cot θ=cot^2 θ sin^2 θ+5 sin θ=0

Find the complete solution of each equation. Express your answer in degrees.
sec^2 θ+sec θ=0 2 cos^2 θ+1=0 cot θ=cot^2 θ sin^2 θ+5 sin θ=0

Two questions that I would really appreciate some hints on:
1) Circles with centers (2,1) and (8,9) have radii 1 and 9, respectively. The equation for a common external tangent can be written in the form y=mx+b with 0<m. What is b? 2) In triangle ABC,

Evaluate cot@/cot@cot3@ + tan@/tan@tan3@

Which of the following expressions have a value of −3–√?
sin(11π/6) cos(5π/3) cot(7π/6) tan(11π/6) cot(2π/3) sin(5π/3) csc(5π/3) cos(7π/6) cos(π/6) csc(2π/3) I think none..but that is not an option...so do I go with cot(7π/6) thanks

Which of the following expressions have a value of –√3?
sin(11π/6) cos(5π/3) cot(7π/6) tan(11π/6) cot(2π/3) sin(5π/3) csc(5π/3) cos(7π/6) cos(π/6) csc(2π/3) I think none..but that is not an option...so do I go with cot(7π/6) thanks

Can someone help me find the exact value of 4csc(3pi/4)cot(pi/4)?
Thanks! cotx =1/tanx cscx = 1/sinx If you find it easier to conceptualize in degrees, realize that pi/4 radians is 45º and 3pi/4 is then 135º If you know the CAST rule, it is easy to see

Someone please help!!!?
7. What is 1/cot(x) in terms of sine? This is what I've got so far: sin = 1/csc tan = 1/cot 1+cot2(x) = csc2(x) 1/1+cot2(x) = 1/csc2(x)

Please show how to do these problems so i understand.
1)Prove that sin^2 x (1+cot^2 x)=1 2)Prove that tan x (cot x+tan x)=sec^2 x

Please show how to do these problems so i understand.
1)Prove that sin^2 x (1+cot^2 x)=1 2)Prove that tan x (cot x+tan x)=sec^2 x

could someone please tell me what the other angle identity of tan is? Thank you much!
"...other angle identity of tan x"? in relation to which "other" ? there are many identities dealing with the tangent. The most important is probably tan x = sin x/cos x

cot (tan + cot) = ?

cot u  cot 2u = cosec 2u

cot^2/1 + cot^2 = cos^2

1)Find cos theta if sin theta=3/5 and 90 degrees<theta<180 degrees.
A)4/5 B)4/5 C)square root of 34/5 D)square root of 34/5 I chose A 2)Simplify:1csc^2theta/cot^2theta A)1 B)1 C)tan^2theta D)1/sin^4theta I chose C 3)Simplify:5(cot^2thetacsc^2theta)

Verify the following:
1. cos x/(1sinx)= sec x + tan x 2. (tanx+1)^2=sec^2x + 2tan x 3. csc x = )cot x + tan x)/sec x 4. sin2x  cot x = cotxcos2x

Let f(x)=cot(x). Determine the points on the graph of f for 0<x<2π where the tangent line(s) is (are) parallel to the line y=−2x.
so i've derived f(x) = cot(x) and have gotten f'(x)=csc^2(x) which then I've made f'(x)=2x so now i have 2x=csc^2(x) or

Which expression is equivalent to tan thetasec theta/sin theta?
A)cot theta B)cot theta C)tan thetacot theta D)tan thetasec^2theta just tell me what I need to know to set it up

sec theta 5 need to find
cos theta cot theta cot (90theta) sin theta not sure what to do completely confused on this stuff

We're doing indefinite integrals using the substitution rule right now in class.
The problem: (integral of) (e^6x)csc(e^6x)cot(e^6x)dx I am calling 'u' my substitution variable. I feel like I've tried every possible substitution, but I still haven't found

Find an equation for the tangent line to the curve at (π/2 , 2).
y = 4 + cot(x)  2csc(x) I am confused how to take the derivative of this problem. When I tried to solve it I ended up with csc^2 (x) + (2csc(x) * cot(x)). From there I can't seem to

Q.1 Prove the following identities:
(i) tan^3x/1+tan^2x + cot^3x/1+cot^2 = 12sin^x cos^x/sinx cosx (ii) (1+cotx+tanx)(sinxcosx)/sec^3xcosec^3x = sin^2xcos^2x.

Q.1 Prove the following identities:
(i) tan^3x/1+tan^2x + cot^3x/1+cot^2 = 12sin^x cos^x/sinx cosx (ii) (1+cotx+tanx)(sinxcosx)/sec^3xcosec^3x = sin^2xcos^2x.

Which of the following are trigonometric identities? Select all that apply (there are 3 answers).
A cos^2(theta)=sin^2(theta)1 B sin(theta)=1/csc(theta) C sec(theta)=1/cot(theta) D cot(theta)=cos/sin(theta) E 1+cot^2(theta)=csc^2(theta)

Use the fundamental identities to simplify the expression:
cot beta sec beta I used 1+tan^2u=secu since cot is the inverse of tan. I flipped the tangent, then so it was 1+ (1/tan). But the book's answer is the cosecant of beta. Where did this come from??

sorry, another I can't figure out
Show that (1cot^2x)/(tan^2x1)=cot^2x I started by factoring both as difference of squares. Would I be better served by writing in terms of sine and cosine? Such as: [1(cos^2x/sin^2x)]/[(sin^2x/cos^2x)1]=(cos^2x/sin^2x)