A firefighter of mass 73 kg slides down a vertical pole with an acceleration of 5 m/s2. The acceleration of gravity is 10m/s2. What is the friction foce that acts on him? Answer in units of N

Fdown = m g

Fup = friction force

F = m a

m g - Fup = m a
so
Fup = m(g-a) = 73 (10 - 5) = 365 Newtons

Fg = m*g = 73 * 10 = 730 N. = Force of gravity.

Fg-Fk = m*a
730-Fk = 73 * 5 = 365 N.
-Fk = 365-730 = -365
Fk = 365 N. = Force of kinetic friction.

Well, isn't this firefighter one brave soul sliding down that pole! Now, let's tackle the problem at hand.

To find the friction force acting on the firefighter, we need to determine the net force acting on him.

The net force is equal to the product of the firefighter's mass (m) and his acceleration (a). In this case, the acceleration is the difference between the downward acceleration due to gravity (g) and his own accelerated downward motion (a):

Net force = m * (g - a)

Now, we can simply plug in the given values:

Net force = 73 kg * (10 m/s^2 - 5 m/s^2)

Calculating this, we find:

Net force = 73 kg * 5 m/s^2

Net force = 365 N

So, the friction force acting on the firefighter is 365 Newtons. Keep sliding, brave firefighter!

To find the friction force acting on the firefighter, we first need to determine the net force acting on him.

The net force can be found by subtracting the gravitational force from the net force equation:

Net Force = Mass * Acceleration

Given:
Mass of the firefighter = 73 kg
Acceleration due to gravity = 10 m/s^2
Acceleration of the firefighter = 5 m/s^2

Net Force = (Mass * Acceleration) - (Mass * Acceleration due to gravity)

Substituting the values:
Net Force = (73 kg * 5 m/s^2) - (73 kg * 10 m/s^2)

Calculating:
Net Force = 365 N - 730 N
Net Force = -365 N

The negative sign indicates that the net force is acting in the opposite direction compared to the acceleration.

Since the firefighter is sliding down the pole, the friction force opposes the downward motion. Therefore, the magnitude of the friction force is equal to the magnitude of the net force:

Friction Force = |Net Force| = |-365 N| = 365 N

Hence, the friction force acting on the firefighter is 365 N.