A science teacher has a supply of 50% sugar solution and a supply of 80% sugar solution. How much of each solution should the teacher mix together to get 105 ML of 60% sugar solution for an experiment
70 ML of the 50% solution and 35 ML of the 80% solution
35 ML of the 50% solution and 70 ML of the 80% solution
70 ML of the 50% solution and 70 ML of the 80% solution
35 ML of the 50% solution and 35 ML of the 80% solution
Lmao its odd seeing so many connections academy kids here. Wassup fam. Btw the answer is 70ml of the 50% solution and 35ml of the 80% solution
hey guys here is the real answers, I'm sorry if they change any questions:
1. A [1.4, 2.2]
2. D [-2, -9.5]
3. C [infinitely many]
4. D [none]
5. C [infinitely many]
6. D [none]
7. C
8. D
9. A [y≥60; 2x+2y≤260]
10. B [4 days]
11. A [$0.50 per cookie; $1.25 per brownie]
12. A
13. A
14. B [1.5, 10]
15. D [5,1]
16. B [750 T-Shirts
17. B [16 quarts...]
18. B [44 mL]
19. C
20. A
21. A [5x+7y≥140]
22. A
23. A
24. D
.5x+.8(105-x)=.6*105
x = x=70
so, (a)
Even without doing the calculation, this can be easily solved.
Since 60% is closer to 50% than it is to 80%, more of the lower concentration will be needed.