Use the Quadratic formula to solve the equation -4x^2-3x+2=0

U5 L6 Quadratic Formula Quick Check 2022:

1. A. -3 βˆ• 8 Β± √41 βˆ• 8
2. C. 14.86 yards
3. A. two real solutions
4. B. no

4/4 100%

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x = (3±√(9+32))/-8

To solve the quadratic equation -4x^2 - 3x + 2 = 0 using the quadratic formula, we need to identify the coefficients first.

The equation is in the form ax^2 + bx + c = 0, where:
a = -4
b = -3
c = 2

Now, we can apply the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

Substituting the values:
x = (βˆ’(βˆ’3) Β± √((βˆ’3)^2 - 4(-4)(2))) / (2(-4))

Simplifying further:
x = (3 ± √(9 + 32)) / -8
x = (3 ± √41) / -8

Therefore, the two solutions to the quadratic equation -4x^2 - 3x + 2 = 0 are:
x = (3 + √41) / -8
x = (3 - √41) / -8

To solve the quadratic equation -4x^2 - 3x + 2 = 0 using the quadratic formula, we need to know the values of the coefficients a, b, and c. In this case, a = -4, b = -3, and c = 2.

The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)

Plugging in the values of a, b, and c into the formula, we have:
x = (-(-3) ± √((-3)^2 - 4*(-4)*(2))) / (2*(-4))
x = (3 ± √(9 + 32)) / (-8)
x = (3 ± √41) / (-8)

So, the two solutions to the equation -4x^2 - 3x + 2 = 0 are:
x = (3 + √41) / (-8)
x = (3 - √41) / (-8)