In a fission reaction, uranium-235 bombarded with a neutron produces strontium-94, another small nucleus, and 3 neutrons. Write the nuclear equation for this reaction.

that should be 54Xe139, not 138

Sure, here's the nuclear equation for the reaction:

Uranium-235 + Neutron -> Strontium-94 + Another Small Nucleus + 3 Neutrons

But I have to wonder, did the uranium and neutron stop for a quick coffee break before producing all those new particles?

To write the nuclear equation for a fission reaction, we need to represent the reactants and products involved in the process. In this case, uranium-235 (U-235) is bombarded by a neutron, resulting in the production of strontium-94 (Sr-94), another small nucleus, and 3 neutrons.

The nuclear equation can be written as follows:

U-235 + n -> Sr-94 + Small nucleus + 3n

Here, "U-235" represents the uranium-235 atom, "n" represents a neutron, "Sr-94" represents the strontium-94 atom, and "Small nucleus" is a placeholder for the other small nucleus formed as a result of the fission. The "+ 3n" indicates the release of three neutrons.

Note that the small nucleus produced can vary in each fission reaction, so its identity is not specified in this equation.

The first numeber is the atomic number followed by the element symbol followed by the mass number; thus 26Co60 is Co 60 (Co is element 26).

92U235 + 0n1 ==> 38Sr94 + yXz + 3 0n1
Atomic numbers must add up.
Mass numbers must add up. Therefore,
92 + 0 = 38 + y + 0. Solve for y = 54 and element 54 is Xe.
Then 235 + 1 = 94 + z + 3 and z = 138
Rxn is
92U235 + 0n1 ==> 38Sr94 + 54Xe138 + 3 0n1