1.00 L of a gas at standard temperature and pressure is compressed to 473 ML. what is the new pressure of the gas?

Well, standard pressure just means 1 atm. The temperature and the moles of the gas will not change. The things that change in this problem are the pressure and volume. Since you already know the volumes, you can solve this problem using Boyle's law:

P1V1 = P2V2
P1 = 1 atm
V1 = 1L x 1000mL/1L = 1000mL
P2 = ?
V2 = 473 mL.

Rearrange the equation for what you want to get, P2:
P2 = P1V1 / V2
P2 = 1 atm x 1000mL / 473mL
P2 = 2.11atm

P1V1=P2V2

P1=1atm, V1=1000ml, V2=473ml
P2=P1V1/V2
=1atm*1000ml/473ml
=2.11atm ANSWER

Yes

Well, you know what they say about gas under pressure - it's like a balloon on a diet, trying to fit into skinny jeans! In this case, the volume has decreased from 1.00 L to 473 mL, so the gas is definitely feeling a bit cramped. But let's not forget about the pressure! Since the temperature is still the same, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature is constant. So, if the volume gets roughly halved, the pressure will roughly double. Therefore, the new pressure of the gas should be around two times the original pressure. But keep in mind, I'm just a Clown Bot, not a mathematician!

To find the new pressure of the gas, we can use Boyle's Law equation:

P1V1 = P2V2

Where:
P1 = initial pressure
V1 = initial volume
P2 = new pressure
V2 = new volume

Given:
P1 = standard pressure = 1 atm
V1 = 1.00 L = 1000 mL
V2 = 473 mL

Substituting the values into the equation:

(1 atm)(1000 mL) = (P2)(473 mL)

Simplifying:

1000 mL atm = (P2)(473 mL)

Now, we can solve for P2 by dividing both sides of the equation by 473 mL:

P2 = (1000 mL atm) / (473 mL)

Calculating:

P2 ≈ 2.11 atm

Therefore, the new pressure of the gas is approximately 2.11 atm.

To find the new pressure of the gas, we can use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume when temperature is constant.

Boyle's Law equation: P1 * V1 = P2 * V2

Where:
P1 = Initial pressure
V1 = Initial volume
P2 = Final pressure (unknown)
V2 = Final volume

Given:
P1 = Standard pressure (at standard temperature and pressure)
V1 = Initial volume = 1.00 L
V2 = Final volume = 473 mL

First, we need to convert the volumes into a consistent unit. We will convert mL to L by dividing by 1000:
V2 = 473 mL ÷ 1000 = 0.473 L

Now, we can substitute the known values into Boyle's Law equation and solve for P2:
P1 * V1 = P2 * V2
1 atm * 1.00 L = P2 * 0.473 L

Next, isolate P2 by dividing both sides of the equation by 0.473 L:
P2 = (1 atm * 1.00 L) / 0.473 L

P2 = 2.113 atm

Therefore, the new pressure of the gas is approximately 2.113 atm.