A microscope is set so it makes an object appear 4x10^2 times larger than its actual size. A virus has a diameter of 2x10^-7 meter. How large will the diameter of the virus appear when it is viewed under the microscope?
4x10^2 * 2x10^-7 = 8x10^-5
Still pretty small, imho.
To find out how large the diameter of the virus will appear when viewed under the microscope, we can multiply the actual diameter of the virus by the magnification factor of the microscope.
Given:
Actual diameter of the virus = 2x10^-7 meter
Magnification factor of the microscope = 4x10^2
To calculate the apparent diameter of the virus when viewed under the microscope:
Apparent Diameter = Actual Diameter x Magnification Factor
Substituting the given values:
Apparent Diameter = (2x10^-7 meter) x (4x10^2)
To simplify the calculation, we can perform the multiplication:
Apparent Diameter = 8x10^-5 meter
Therefore, the diameter of the virus will appear to be 8x10^-5 meter when viewed under the microscope.
To determine how large the diameter of the virus will appear when viewed under the microscope, we can use the magnification factor provided.
The magnification factor of 4x10^2 means that the microscope makes an object appear 400 times larger than its actual size.
Let's calculate the diameter of the virus when viewed under the microscope:
Step 1: Calculate the magnified diameter of the virus.
- Diameter of the virus = 2x10^-7 meter
- Magnification factor = 400
Magnified diameter = Diameter of the virus x Magnification factor
Magnified diameter = 2x10^-7 meter x 400
Magnified diameter = 8x10^-5 meter
Therefore, the diameter of the virus will appear as 8x10^-5 meter when viewed under the microscope.