ACTIVATED SLUDGE AND NUTRIENT REMOVAL
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A wastewater treatment plant based on activated sludge with biological phosphate and nitrogen removal via pre-denitrification. The influent flow (dwf) is 30,000 m3/day and the influent BOD concentration is
300 mg BOD/l. The suspended solid concentration in the influent is 150 mg/l of which 40% is removed in the primary clarifier. The sludge recycle flow ratio (fr) is 0.5, the sludge yield (Y) is 0.6 kgX/kgBODremoved and the SVI is 130 mL/g.
The treatment plant consists of different process units, namely:
Final clarifier
Screen
Aerobic tank
Primary sedimentation
Anoxic tank
Grit chamber
Anaerobic tank
Sludge dewatering
After dewatering the sludge will be directly transported to the sludge incineration plant.
Q1:What is the minimum size (volume) in m3 of the aeration tank?
Calculate with a biomass concentration in the aeration tank of 4 g/l and take into account that the primary settler removes 33% of the BOD.
Q2:What would be the size (volume) in m3 of the anaerobic tank (don’t forget the sludge recycle flow to the anaerobic tank)?
Q3:What would be the waste activated sludge (or surplus sludge production) in kg dry weight per day?
Calculate the biomass production assuming all BOD entering the biological process is removed. Also add the primary sludge production, but for simplicity neglect the remainder of the suspended solids.
The biomass production (kg biomass per day) is:?
The primary sludge production (kg per day) is:?
Q4:The sludge is directly dewatered to a final dry solid concentration of 18%. How much trucks, that can transport a load of 30 ton, will be needed per year for sludge transport to the incineration plant?
Q5:How can the produced sludge be reduced maximally, to minimize transport costs?
a//Application of chemical conditioning .b//Application of sludge digestion.c// By thickening of the primary sludge
Question 3d
What would be the size (volume) in m3 of the anaerobic tank (don’t forget the sludge recycle flow to the anaerobic tank)?
Answer =1875
2C1=1.22
2C2=0.34 (velocity) 2C2=32(head loss)
2D2 length=11.85
width=0.79
hight= 0.43
grit chanel=0.78
2E
any one can answer this please?? thank you
please tell all the answers for WEb and WEc
thank you Anonymous i got already answer.
Can you help me with answers of this question? I would be grateful :)
please tell the answers ham i wanna pass this , please!!_/\_
screen -->coarse material
grit chamber -->xxx
primary sedimentation -->xxx
anaerobic tank-->xxxx
anoxic tank--->xxxx
aerobic tank-->nitrification
final clarifier-->xxxx
sludge dewatering -->remove water from the sludge
help me with Q3C Q3D Q3E
what answer you want pls?/
1.Screen>>coarse material
2. Grit chamber>>sand
3.Primary Sedimentation >>Suspended solid & settle able part of BOD
4.Anaerobic tank >>Hydrolysis of Xs & uptake of Ss
5.Anoxic tank >>Denitrification
6.Aerobic tank >>Nitrification
7.Final clarifier >>Separating Biomass & effluent
8.Sludge De watering >> remove water from sludge.