if the specifc heat of iron = 0.46J/g C,how much heat is needed to warm 50g of iron from 20C to 100C
-- I do not know how to make the celcius o above the temperature number
my anwswer
Q = Mx(delta)TxC
Q=50gx80Cx0.46J/gC
Q = 1840 Joules
Delta = the triangle I do not know how to make that on the computer
I don't know how to make the delta on the computer either. I usually write as you did. I note that some students use DH for delta H, DT for delta T, DS for delta S, etc.
You answer of 1840 Joules is correct. Good work.
A couple of points I missed. I CAN make the degree sign as 20o C. But it's a lot easier to just write it as 20o C and almost everyone knows what that means. The other point is to please not the correct spelling of Celsius.
To warm 50g of iron from 20°C to 100°C, we can use the equation Q = (mass) x (change in temperature) x (specific heat).
First, let's calculate the change in temperature:
(change in temperature) = (final temperature) - (initial temperature)
= 100°C - 20°C
= 80°C
Now, we can calculate the amount of heat required:
Q = (mass) x (change in temperature) x (specific heat)
= 50g x 80°C x 0.46J/g°C
= 1840 Joules
To find the amount of heat needed to warm 50g of iron from 20°C to 100°C, we can use the formula:
Q = M x (delta)T x C
Q represents the amount of heat, M represents the mass of the substance (in this case, 50g), (delta)T represents the change in temperature (final temperature - initial temperature), and C represents the specific heat capacity of the substance (in this case, 0.46J/g°C for iron).
First, calculate the change in temperature:
(delta)T = final temperature - initial temperature
(delta)T = 100°C - 20°C
(delta)T = 80°C
Next, substitute the values into the formula:
Q = 50g x 80°C x 0.46J/g°C
Q = 1840 Joules
Therefore, the amount of heat needed to warm 50g of iron from 20°C to 100°C is 1840 Joules.