What is the final volume of NaOH solution prepared from 250.0mL of 0.800M NaOH if you wanted the final concentration to be 0.200M
c1v1 = c2v2
c = concn
v = volume
250 mL x 0.800M = mL x 0.200M
Solve for mL
1000
To determine the final volume of NaOH solution, we can use the dilution formula:
M1 * V1 = M2 * V2
Where:
M1 = initial concentration of NaOH
V1 = initial volume of NaOH
M2 = final concentration of NaOH
V2 = final volume of NaOH
Let's substitute the given values into the formula:
(0.800 M) * (250.0 mL) = (0.200 M) * V2
Now, we can solve for V2:
(0.800 M * 250.0 mL) / 0.200 M = V2
V2 = 1000 mL
Therefore, the final volume of NaOH solution needed to prepare a 0.200 M solution from 250.0 mL of 0.800 M NaOH is 1000 mL or 1.00 L.
To find the final volume of NaOH solution, we can use the dilution formula:
C1 * V1 = C2 * V2
Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
In this case, we have:
C1 = 0.800 M (initial concentration)
V1 = 250.0 mL (initial volume)
C2 = 0.200 M (final concentration)
V2 = ?
To find V2, we can rearrange the formula:
V2 = (C1 * V1) / C2
Now let's substitute the given values into the equation:
V2 = (0.800 M * 250.0 mL) / 0.200 M
First, multiply the initial concentration (C1) by the initial volume (V1):
V2 = (0.800 M * 250.0 mL)
Then divide the result by the final concentration (C2):
V2 = (200.0 mL) / 0.200 M
Finally, calculate the result:
V2 = 1000.0 mL
Therefore, the final volume of the NaOH solution will be 1000.0 mL or 1.0 L.