When a skydiver jumps from an airplane, the distance d in feet the diver falls in t seconds before opening the parachute is given by the formula d=16t^2. The formula assumes that there is no air resistance. Find the time it takes a skydiver to fall 1,551 ft before opening the parachute. Round to the nearest tenth.
a) 9.7 s
b) 9.8 s
c) 9.9 s
d) 2.5 s
is the answer b ?
yes. good work.
yes
9.8
The answer is 9.8s
But how do you figure out how to get to 9.8?
To find the time it takes for a skydiver to fall 1,551 ft, we can use the equation d = 16t^2 and solve for t.
The equation is given by d = 16t^2, where d is the distance in feet and t is the time in seconds.
Substituting the given distance of 1,551 ft, we have:
1,551 = 16t^2.
To solve for t, we need to isolate the variable t. Divide both sides of the equation by 16:
1,551/16 = (16t^2)/16.
Simplifying, we get:
96.9375 = t^2.
Now, take the square root of both sides:
√96.9375 = √(t^2).
Calculating the square root, we find:
9.846 = t.
Rounding to the nearest tenth, the time it takes the skydiver to fall 1,551 ft before opening the parachute is 9.8 seconds.
Therefore, the correct answer is option b) 9.8 s.