The sum of two consecutive even integers is 122. What are the integers?
if the numbers were the same, they'd both be 61
So, try 60 and 62.
Algebraically, if x is the smaller number,
x + x+2 = 122
2x = 120
x = 60
Well, let's try to solve this using some clown logic, shall we?
Let's imagine the first integer is X. Now, since we're dealing with even numbers, the next consecutive even number must be X + 2.
According to the problem, the sum of these two numbers is 122. So, we can set up the equation: X + (X + 2) = 122.
Simplifying this equation, we get 2X + 2 = 122.
Subtracting 2 from both sides, we're left with 2X = 120.
Finally, dividing both sides by 2, we find that X = 60.
So, the first even integer is 60, and the next consecutive even integer is 60 + 2, which is 62.
Therefore, the two consecutive even integers that add up to 122 are 60 and 62.
Hope that clown logic didn't make your head spin too much!
Let's represent the first even integer as "x". Since the second even integer is consecutive, it will be "x+2".
According to the problem, the sum of these two consecutive even integers is 122. We can set up the following equation to represent this:
x + (x+2) = 122
Now, let's solve the equation step-by-step:
1. Combine like terms: x + x + 2 = 122
This simplifies to: 2x + 2 = 122
2. Subtract 2 from both sides of the equation to isolate the variable term:
2x + 2 - 2 = 122 - 2
This simplifies to: 2x = 120
3. Divide both sides of the equation by 2 to solve for x:
2x / 2 = 120 / 2
This simplifies to: x = 60
Now that we have found the value of x, we can substitute it back into our equation to find the second even integer:
x + 2 = 60 + 2
So, the second even integer is 62.
Therefore, the two consecutive even integers that sum up to 122 are 60 and 62.
To find the consecutive even integers, we can start by setting up an equation. Let's assume the first even integer is x.
Since consecutive even integers are always 2 units apart, the second even integer would be x + 2.
According to the problem, the sum of these two consecutive even integers is 122. Thus, we can write the equation:
x + (x + 2) = 122
Simplifying the equation, we combine like terms:
2x + 2 = 122
Next, we isolate the variable by subtracting 2 from both sides of the equation:
2x = 120
To solve for x, we divide both sides by 2:
x = 60
Therefore, the first even integer is 60. To find the second even integer, we add 2 to the first even integer:
60 + 2 = 62
Hence, the two consecutive even integers are 60 and 62.