Which of the compounds below exhibit geometric isomerism (cis-, trans-)?
1-chloro-1-pentene
1-heptene
1,2-dimethylcyclopentene
2-methyl-3-hexene
2-methyl-2-butene
1-methylcyclopentane
1,2-dimethylcyclohexane
here's what i got:
1-chloro-1-pentene - yes
1-heptene - no
1,2-dimethylcyclopentene - Yes
2-methyl-3-hexene - yes
2-methyl-2-butene - Yes
1-methylcyclopentane -Yes
1,2-dimethylcyclohexane - No
but my answer doesn't seem to be correct. please help
I'm not an organic chemist AND I have trouble visualizing these in my mind, but I think 1 methylcyclopentane is no. There are no double bonds. I have trouble with 1,2-dimethylcyclopentene but you're probably right. The others I would agree with you. If you are putting your answers into a data base post to let me know if my answer is ok.
well i can't check to see if these are correct because it doesn't tell me.
i looked them up online. Here is what i found online.
chemicalforums . com/index.php?topic=25938.0#msg97599
please verify these answers because this homework is worth alot of points
It is 2
To determine whether a compound exhibits geometric isomerism (cis-, trans-), we need to evaluate the presence of a double bond or a ring in the molecule. Here's how you can identify geometric isomers for each compound:
1-chloro-1-pentene:
This compound has a double bond, so it can exhibit geometric isomerism. The chlorine atom is not relevant to the isomerism.
1-heptene:
Since it has a double bond, 1-heptene can exhibit geometric isomerism, as long as there are different groups on each side of the double bond.
1,2-dimethylcyclopentene:
This compound has a double bond embedded in a cyclic structure. Molecules with a ring structure can exhibit geometric isomerism if there are different groups attached to the carbons involved in the double bond. Therefore, 1,2-dimethylcyclopentene can exhibit geometric isomerism.
2-methyl-3-hexene:
Similar to 1-heptene, this compound has a double bond, so it can exhibit geometric isomerism.
2-methyl-2-butene:
This compound has a double bond, so it can exhibit geometric isomerism. The placement of groups around the double bond will determine whether it is cis- or trans-.
1-methylcyclopentane:
This compound does not have a double bond, so it cannot exhibit geometric isomerism. The presence of the methyl group does not affect the isomerism.
1,2-dimethylcyclohexane:
Similar to 1-methylcyclopentane, this compound does not have a double bond and cannot exhibit geometric isomerism.
Therefore, the compounds that exhibit geometric isomerism are:
1-chloro-1-pentene
1-heptene
1,2-dimethylcyclopentene
2-methyl-3-hexene
2-methyl-2-butene
Please note that your original answer was mostly correct, except for 1-heptene, which can exhibit geometric isomerism.