1. Translate P(4,0) right 3 units and up 5 units. Give the coordinates of the image point.
(-5,1)
(1,-5)
(5,7)
(7,5)
2. Point A(6, -2) is reflected over the x-axis. Write the coordinates of A'.
6,2
6,-2
-6,2
-6,-2
1. To translate a point right 3 units, we add 3 to the x-coordinate. To translate a point up 5 units, we add 5 to the y-coordinate.
Given the original point P(4,0), we can apply the translations step by step:
Step 1: Translate right 3 units. Adding 3 to the x-coordinate, we get: x + 3 = 4 + 3 = 7.
After translating right 3 units, the x-coordinate becomes 7.
Step 2: Translate up 5 units. Adding 5 to the y-coordinate, we get: y + 5 = 0 + 5 = 5.
After translating up 5 units, the y-coordinate becomes 5.
Therefore, the image point after the translations is (7, 5).
2. To reflect a point over the x-axis, we keep the x-coordinate the same and change the sign of the y-coordinate.
Given the original point A(6, -2), we can reflect it over the x-axis as follows:
The x-coordinate remains the same: x = 6.
The y-coordinate changes sign: -y = -(-2) = 2.
Therefore, the coordinates of the reflected point A' are (6, 2).
B, c
just add (4,0)+(3,5)
reflect in x-axis moves (x,y) to (x,-y)
so, where does (6,-2) go? (6,-(-2))