The domain of f(x)=(1)/(sqrt(x^26x7)) is
(1, 7)
[1, 7]
x > 1 or x < 7
***{x < 1}U{x > 7}
(∞, 1]U[7, ∞)
2. In which of the following is y a function of x?
I. y^2=9x^2
II. y=x
III. y=(sqrt(x^2))^3
I only
II only
III only
***I and III only
I, II and III
3. You would probably use calculus to determine the area for which of the following shapes?
***(infinity symbol)
(rectangle)
(triangle)
(arrow)
(plus sign)
4. If g(x)=3x−1 and f(x)=(sqrt(9x^2)) , then which of the following will have a domain of: [−3, 1/3) ∪ (1/3, 3]?
(g + f)(x)
(f/g)(x)
(g − f)(x)
***g(f(x))
f(g(x))
5. Which of the following is always true of odd functions?
I. f(x)=f(x)
II.f(x) is even
III. f(x) is even
All of these are true.
None of these are true.
I only.
II only.
***I and III only.
6. If f(x)= 3/(x3), then f^1(x)=
(x3)/3
(x+3)/3
***3/(x+3)
3/(x3)
No inverse exists.
7. The function f(x) = −x − b intersects g(x) = 2(x − 4)^2 at exactly one point. The value of b is:
5
***4
5
4
Any real number
8. If a right circular cone must have a volume of 12 cubic meters, then a function that gives the possible radii as a function of the height is:
r=12/pi*h
r=+(sqrt(36/pi*h))
***r=(sqrt(36/pi*h))
h=(sqrt(36/pi*r^2))
r=36/(pi*h)
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4 answers

#1 ok
#2 III only
for y to be a function of x, each x must map to only one y.
#3 ok
#4 (f/g)(x)
f has domain [3,3]
g has domain x≠1/3
#5 all of the above
f(x) = f(x)
#6 Hmmm. I get 3(x+1)/x = 3/x + 3
That's your choice without the parentheses
#7 +4
#8 ok 👍
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answered by Steve 
Thank you!! Unfortunately I couldn't wait for your response, but I went over my answers before checking to see if they were right, and I got them all right! Thank you so much for your help! It means the world to me, and will count on you if I need help on more topics in Calculus. :)
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answered by Samantha 
Hey Samantha, were his answers right or were yours?
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answered by V 
his answers are right
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answered by shh
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