Two identical cars (m = 1350 kg) are traveling at the same speed of 28.1 m/s. They are moving in the directions shown in the drawing. What is the magnitude of the total momentum of the two cars?

p=mv

First find the resultant of the two velocity vectors by using the Pythagorean theorem. Since the cars are identical, the velocities are the same.

find the sq. root of (28.1^2)+(28.1^2)

you should get 39.7394011 after you find the sq. root.
multiply your answer by the mass:
39.7394011*1350 and you should get your answer.

hope this helped:)

My bad. I didnt read closely enough. Finding the square root of the velocity squared plus the velocity squared and multiplying that by the mass did get me the right answer

Well, if we're talking about the total momentum of both cars, we need to take into account both their masses and velocities. Since both cars are identical, we'll just double the mass of one car.

So, the total momentum is equal to the mass multiplied by the velocity. Let's calculate it:

Momentum of one car = mass × velocity = 1350 kg × 28.1 m/s = 37,935 kg·m/s

Since we have two cars with the same speed, we just need to double this momentum:

Total momentum = 2 × Momentum of one car = 2 × 37,935 kg·m/s = 75,870 kg·m/s

So, the magnitude of the total momentum of the two cars is 75,870 kg·m/s. That's quite a momentum! They must be in a hurry to get somewhere!

To calculate the magnitude of the total momentum of the two cars, we need to first calculate the momentum of each car individually and then add them together.

The momentum of an object is given by the formula:
Momentum = mass x velocity

Given that the mass of each car is 1350 kg and the velocity of both cars is 28.1 m/s, we can calculate the momentum of each car.

Momentum of one car = mass x velocity = 1350 kg x 28.1 m/s
= 37935 kg⋅m/s

Since both cars are identical, both will have the same momentum.

To find the magnitude of the total momentum, we add the momentum of each car.
Total momentum = Momentum of one car + Momentum of the other car
= 37935 kg⋅m/s + 37935 kg⋅m/s
= 75870 kg⋅m/s

Therefore, the magnitude of the total momentum of the two cars is 75870 kg⋅m/s.

I got 44.74651644 for the resultant vector car a is going 60 degrees from the positive y axis going left. The other is going north east 30 degrees from the y axis. I'm assuming the deprzwing is the same, but both answers are incorrect.