A graduated cylinder contains 155mL mL of water. A 17.0g g piece of iron (density = 7.86g/cm 3 g/cm^3 ) and a 23.0g g piece of lead are added. What is the new water level in the cylinder?
You MUST have the density of Pb which is about 11.3 g/mL
volume = mass/density
volume Fe = 17.0/7.86 = ? mL
volume Pb = 23.0/11.3 = ? mL
Total volume Pb + Fe = ?
Volume of water level in graduated cylinder is 155 mL + total volume Pb + Fe = ?
To find the new water level in the cylinder after adding the iron and lead pieces, we need to calculate the total volume of the iron and lead and then subtract it from the initial volume of water in the cylinder.
Let's calculate the volume of the iron first:
Given: Mass of iron = 17.0 g
Density of iron = 7.86 g/cm^3
The volume of iron can be calculated using the formula:
Volume = Mass / Density
Volume of iron = 17.0 g / 7.86 g/cm^3
Volume of iron = 2.163 cm^3
Now let's calculate the volume of the lead:
Given: Mass of lead = 23.0 g
Density of lead = Unknown (we need to assume a value for lead's density)
Unfortunately, we don't know the density of lead in this problem. Please provide the correct density value for lead.
To find the new water level in the graduated cylinder after adding the pieces of iron and lead, we need to consider the change in volume caused by the addition of these objects.
First, we need to find the volume of each object. The volume of an object can be calculated using the formula:
Volume = Mass / Density
For the iron piece:
Volume of iron = 17.0 g / 7.86 g/cm^3 ≈ 2.165 cm^3
For the lead piece:
Volume of lead = 23.0 g / 11.3 g/cm^3 (density of lead) ≈ 2.042 cm^3
Next, we need to find the total change in volume caused by adding both objects:
Total change in volume = Volume of iron + Volume of lead ≈ 2.165 cm^3 + 2.042 cm^3 ≈ 4.207 cm^3
Now, we can calculate the new water level by subtracting the change in volume from the initial water level.
New water level = Initial water level - Total change in volume
The initial water level in the cylinder is given as 155 mL. However, the volume of water needs to be converted to cm^3 to match the volume units used for the objects.
Converting 155 mL to cm^3:
1 mL = 1 cm^3
So, 155 mL = 155 cm^3
Finally, we can calculate the new water level:
New water level = 155 cm^3 - 4.207 cm^3 ≈ 150.793 cm^3
Therefore, the new water level in the graduated cylinder is approximately 150.793 cm^3.