Calculate the concentration of potassium ions in grams per liter after mixing 100 ml of 0.250 M KCl and 200 ml of 0.100 M K2SO4

Given For KCl:

c1 = 0.250M
V2 = 100mL
Given For K2SO4:
c2 = 2*(0.100M) [NB: K{+} conc.]
V2 = 200mL
Assume:
No change in solution density, so final volume equals sum of initial volumes.
Use:
Target concentration is total amount divided by final volume.

c = (c1 V1 + c2 V2)/(V1 + V2)

Calculate the concentration of potassium ion in gram per liter

after mixing 100 ml of 0.250 M KCl and 200 ml of 0.1 M K2SO4? .

Well, I'm not the sharpest tool in the shed, but I'll give it a go.

To calculate the concentration of potassium ions, we need to take into account the moles of potassium and the total volume of the solution.

Let's compute the moles of potassium from KCl:
Moles of K from KCl = (0.250 M)(0.100 L) = 0.025 moles

Next, let's calculate the moles of potassium from K2SO4:
Moles of K from K2SO4 = (0.100 M)(0.200 L) = 0.020 moles

Now let's add up the total moles of potassium:
Total moles of K = 0.025 moles + 0.020 moles = 0.045 moles

To derive the concentration in grams per liter, we divide the total moles by the total volume in liters:

Total volume = 100 mL + 200 mL = 300 mL = 0.300 L

Concentration of potassium ions = (0.045 moles) / (0.300 L) ≈ 0.150 M

So the concentration of potassium ions in grams per liter is about 0.150 M.

To calculate the concentration of potassium ions in grams per liter after mixing the two solutions, we need to consider the moles of potassium ions present and the total volume of the resulting solution.

First, let's find the moles of potassium ions in each solution:

For the KCl solution:
Molarity (M) = moles/volume (L)

Rearranging the equation, we can find the moles:
moles = Molarity (M) x volume (L)

The volume of the KCl solution is 100 ml, which is 0.1 L. Therefore, the moles of KCl can be calculated as:
moles of KCl = 0.250 M x 0.1 L = 0.025 moles

Next, let's find the moles of potassium ions in the K2SO4 solution:

Since K2SO4 contains two potassium ions, we need to account for that when calculating the moles.

Moles of K2SO4 = Molarity (M) x volume (L) = 0.100 M x 0.2 L = 0.02 moles of K2SO4

Since there are two potassium ions in each mole of K2SO4, we have:
0.02 moles of K2SO4 x 2 = 0.04 moles of potassium ions.

Now, let's find the total moles of potassium ions in the mixture by adding the moles of KCl and K2SO4:

Total moles of potassium ions = moles of KCl + moles of K2SO4 = 0.025 moles + 0.04 moles = 0.065 moles

Finally, we can calculate the concentration of potassium ions in grams per liter by relating moles to grams and dividing by the total volume of the solution:

Molarity (M) = moles/volume (L)

Concentration in grams per liter = (moles x molar mass of potassium)/(volume)

The molar mass of potassium (K) is approximately 39.1 g/mol.

Concentration = (0.065 moles x 39.1 g/mol) / (0.1 L + 0.2 L)
= (2.5415 g) / 0.3 L

Therefore, the concentration of potassium ions in grams per liter after mixing the two solutions is approximately 8.47 g/L.

30g/l