Gloria's garden plot is one foot wider and three feet shorter than last year garden but has the same area. What were the dimensions of the garden last year?
Thx for le answer lol
I don't know what it is. I'm trying to answer the question,dang it.
To find the dimensions of Gloria's garden last year, we need to set up an equation based on the given information.
Let's assume the width of last year's garden is x feet.
According to the given information, this year's garden is one foot wider, so its width would be x + 1 feet.
Similarly, let's assume the length of last year's garden is y feet.
According to the given information, this year's garden is three feet shorter, so its length would be y - 3 feet.
The area of a rectangle is given by multiplying its length by its width. Since the area of this year's garden is the same as last year's garden, we can set up the following equation:
x * y = (x + 1) * (y - 3)
Now, let's solve this equation to find the dimensions of the garden last year.
Expanding the equation:
xy = xy - 3x + y - 3
Rearranging terms:
xy - xy + 3x - y = -3
Combining like terms:
3x - y = -3
Now, we have an equation with two variables, x and y. However, we need more information to determine the exact values of x and y. If there were additional information provided in the question, we could solve for the dimensions of the garden last year by substituting the values back into the equation.
(x+1)(y-3) = xy
y-3x-3 = 0
y = 3(x+1)
possible solutions
Last year : this year
1x6 : 2x3
2x9 : 3x6
...
15 and 4
15*4=60
-3 +1=
12 and 5
12*5=60