A staging that weighs Wstaging supports a painter weighing 620 N. The reading on the left scale is 660 N and the reading on the right scale is 410 N. What is the weight of the staging? Answer in units of N

Make a free body diagram of the staging.

Sum forces acting on the staging, and the total should be zero.

Upward (reaction) forces=660+410=1070 N
Downward forces = 620 N + W
Sum to zero
620+W=660+410
W=660+410-620
=450 N.

Well, well, well! Looks like the staging is feeling a little heavy, eh?

Let's do some weighty calculations here. The weight on the left scale is 660 N, and the weight on the right scale is 410 N.

Since the staging is acting as a support for the painter, we can think of this as a balancing act. The total weight on the left side of the staging (painter + staging) is 660 N, and on the right side is 410 N.

To find the weight of the staging, we need to make the left and right sides even. It's like restoring balance to the universe, or at least to this staging.

So, to balance things out, we need to subtract the weight of the painter from the left scale.

660 N - 620 N = 40 N

Voila! The weight of the staging is a cool 40 N.

To find the weight of the staging, we can use the fact that the sum of the forces in equilibrium is equal to zero.

Since the painter weighs 620 N, we can represent this force as Fpainter = 620 N.

Let's assume the weight of the staging is Wstaging.

According to the information given, the reading on the left scale is 660 N and the reading on the right scale is 410 N.

Considering the forces acting on the staging, we have the following equations:

Left scale reading (660 N) - Wstaging - Painter (620 N) = 0
Right scale reading (410 N) - Wstaging = 0

Now, we can solve these equations to find the weight of the staging:

660 N - Wstaging - 620 N = 0
Wstaging - 410 N = 0

Simplifying these equations, we get:

660 N - Wstaging = 620 N
Wstaging = 410 N

Therefore, the weight of the staging is 410 N.

To find the weight of the staging, we need to consider the forces acting on it. In this scenario, we have two scales - one on the left and one on the right - that are measuring the forces.

Let's analyze the forces acting on the staging:
1. The weight of the painter, which is 620 N, is acting downward.
2. The weight of the staging itself, which we need to find, is acting downward.
3. The normal force on the left scale is acting upward.
4. The normal force on the right scale is acting upward.
5. The reading on the left scale is 660 N, and the reading on the right scale is 410 N.

Since the staging is in equilibrium (not accelerating), the sum of the forces in the vertical direction must be zero. This means that the downward forces must balance out the upward forces.

Let's set up an equation:

620 N (painter's weight) + Wstaging (weight of the staging) - 660 N (reading on the left scale) - 410 N (reading on the right scale) = 0

Rearranging the equation, we can solve for Wstaging:

Wstaging = 660 N + 410 N - 620 N
Wstaging = 450 N

Therefore, the weight of the staging is 450 N.