Is (0, 3) a solution to the equation y = x + 3?

I think yes.

Is (1, −4) a solution to the equation y = −2x?
I think no

3. Look at the following points.

(4, 0), (3, −1), (6, 3), (2, −4)

Which are solutions to y = x − 4? Choose all correct answers.

There are 8 crackers in 1 serving, 16 crackers in 2 servings, 24 crackers in 3 servings, and so on. How many crackers are in a box of 12 servings?

a. 80
b. 96
c. 108
d. 120

1.A

2.B
3.B,C
4.B

I know that the last one is 96

#1,2 ok

#3. 1st two only

sor for 3 4, 0 and 3 -1

And this is my last one

How can you use an equation to make a prediction from a pattern?

Q1: Yes, (0, 3) is a solution. It's basically saying "If you have zero clowns, you still have three humor points."

Q2: No, (1, -4) is not a solution. It's like saying "If you have one clown, you'll have negative four laughs. That's just sad clown territory."

Q3: The points (4, 0), (3, -1), and (2, -4) are solutions to y = x - 4. It's as if they're saying "If you take away 4 from the x-coordinate, you'll find the y-coordinate laughing its socks off."

Q4: Well, if there are 8 crackers in 1 serving, then in 12 servings, we would have... (pauses for dramatic effect)... 96 crackers. So the answer is (b) 96. It's a crackerjack of a calculation!

To determine if a given point is a solution to an equation, we substitute the coordinates of the point into the equation and check if it holds true.

1. For the equation y = x + 3, we can substitute the x and y values of (0, 3) into the equation:
y = x + 3
3 = 0 + 3
This is true, so (0, 3) is indeed a solution to the equation.

2. For the equation y = -2x, we can substitute the x and y values of (1, -4) into the equation:
y = -2x
-4 = -2(1)
-4 = -2
This is false, so (1, -4) is not a solution to the equation.

3. For the equation y = x - 4, we can substitute the x and y values of the given points into the equation and check if it holds true for any of them:
For (4, 0), we have: 0 = 4 - 4, which is true.
For (3, -1), we have: -1 = 3 - 4, which is true.
For (6, 3), we have: 3 = 6 - 4, which is true.
For (2, -4), we have: -4 = 2 - 4, which is true.
Therefore, all four points are solutions to the equation y = x - 4.

To determine how many crackers are in a box of 12 servings, we can calculate the pattern of the number of crackers in each serving:

1 serving = 8 crackers
2 servings = 16 crackers (2 times 8)
3 servings = 24 crackers (3 times 8)

From this pattern, we can see that the number of crackers in each serving is multiplied by the number of servings. Therefore, to find the total number of crackers in 12 servings, we multiply the number of servings (12) by the number of crackers in each serving (8):

12 servings * 8 crackers = 96 crackers

Therefore, there are 96 crackers in a box of 12 servings. The correct option is b. 96.