The coordinates of the vertices of a quadrilateral are R(-1,3) S(3,3) T(5,-1), and U(-2,-1).Find the perimeter of the quadrilateral. Round to the nearest tenth.

TU is wrong it's (square root) (5+2)squared+(-1+1)squared=7

Graph it out and use the Pythagorean theorem to find 2 sides. Multiply those together.

The sides have lengths

RS: √((3+1)^2+(3-3)^2) = 4
ST: √((5-3)^2+(-1-3)^2) = √20
TU: √((2-5)^2+(-1+1)^2) = 3
UR: √((-2+1)^2+(-1-3)^2) = √17

so, add them up

19.6 units

32

The coordinates of the vertices of a quadrilateral are A(-1, 3), B(3, 3), C(5, -

1), and D(-2, -1). Find the perimeter of the quadrilateral.
b. What type of triangle is formed by the vertices A(-2, 1), B(3, 2), C(0, -2).

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