A gear with 60 teeth is meshed to a gear with 40 teeth. If the larger gear revolves at 20 revolutions per minute, how many revolutions does the smaller gear make in a minute?
not just an answer please
(A)13 1/3
(B)3
(C)300
(D)120
(E)30
The total teeth per minute on both gears must be the same, so
60*20 = 40x
x = 30
To determine how many revolutions the smaller gear makes in a minute, we need to use the concept of gear ratios. The gear ratio expresses the relationship between the number of teeth on two gears.
In this case, the gear ratio between the larger gear (60 teeth) and the smaller gear (40 teeth) is calculated as follows:
Gear Ratio = Number of teeth on the larger gear / Number of teeth on the smaller gear
So, the gear ratio in this case is 60/40 = 1.5.
Now, since the larger gear revolves at 20 revolutions per minute, we can calculate the number of revolutions the smaller gear makes by multiplying the number of revolutions of the larger gear by the gear ratio:
Number of revolutions of the smaller gear = Number of revolutions of the larger gear * Gear ratio
Number of revolutions of the smaller gear = 20 * 1.5 = 30
Therefore, the smaller gear makes 30 revolutions in a minute.
The correct answer is (E) 30.