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A ball is thrown straight downward from the top of a tall building, with an initial speed of 30 ft/s. Suppose the ball strikes the ground with a speed of 190 ft/s. How tall is the building? Acceleration is -32 ft/s squared

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2 answers
  1. V^2 = Vo^2 + 2g*h
    h = (V^2-Vo^2)/2g
    h = ((190)^2-(30)^2)/64 = 550 Fi.

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  2. height = -16t^2 -30t + d, where d is the height of the building
    d(height)/dt = velocity = -32t - 30
    -190 = -32t - 30
    32t = + 160
    t = 5

    at t = 5 , height = 0
    0 = -16(25) - 150 + d
    550 = d

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