Write a balanced net ionic equation (include physical states) for the following reaction: HClO2(aq)+NaOH(aq)=H2O(l)+NaClO2(aq)
DrBob222 is right, disregard downvotes, people don't know how to read text apparently.
HClO2(aq) + OH^-(aq) ==> H2O(l) + ClO2^-(aq)
Can confirm that DrBob222 is right.
Sure, here's a balanced net ionic equation for the given reaction:
HClO2(aq) + NaOH(aq) → H2O(l) + NaClO2(aq)
Breaking it down into ions:
H+(aq) + ClO2-(aq) + Na+(aq) + OH-(aq) → H2O(l) + Na+(aq) + ClO2-(aq)
In a balanced net ionic equation, the spectator ions (ions that are present on both sides of the equation and do not participate in the reaction) are canceled out. In this case, Na+ and ClO2- do not change, so they are spectator ions.
Simplifying the equation further:
H+(aq) + OH-(aq) → H2O(l)
This is the final balanced net ionic equation, where the hydrochloric acid (HClO2) reacts with sodium hydroxide (NaOH) to produce water (H2O).
To write a balanced net ionic equation for the reaction between HClO2(aq) and NaOH(aq), we first need to write the balanced molecular equation:
HClO2(aq) + NaOH(aq) → H2O(l) + NaClO2(aq)
Next, we need to determine the dissociation of each compound into its respective ions based on their solubility. HClO2(aq) can be dissociated into H+(aq) and ClO2-(aq), while NaOH(aq) can dissociate into Na+(aq) and OH-(aq).
Therefore, the complete ionic equation can be written as follows (splitting the reactants and products into their ions):
H+(aq) + ClO2-(aq) + Na+(aq) + OH-(aq) → H2O(l) + Na+(aq) + ClO2-(aq)
Now we can cancel out the spectator ions (ions that appear on both sides of the equation and do not participate in the reaction) which are Na+ and ClO2-. We are left with:
H+(aq) + OH-(aq) → H2O(l)
This is the net ionic equation for the reaction between HClO2(aq) and NaOH(aq). It represents the essential chemical change that occurs, without including the spectator ions.