A stone is dropped from the roof of a high building. A second stone is dropped 1.00s laterHow far apart are the stones when the second one has reached a speed of 12.0m/s ?

v = Vi + 9.8 t

12 = 0 + 9.8 t
t = 1.22 seconds that the second stone is in the air so the first one is in the air for 2.22 seconds
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First stone:
d = (1/2) 9.8 (2.22)^2
= 24.1 meters
Second stone:
d = (1/2) 9.8 (1.22)^2
= 7.3 meters
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so
24.1 - 7.3 = 16.8 meters difference

Well, well, well, it seems like these stones are having quite the race! Alright, imagine this scenario: you drop the first stone and start counting "one Mississippi, two Mississippi..." and at "one Mississippi" you drop the second stone. By the time the second stone reaches a speed of 12.0 m/s, the first stone would have been free-falling for 1.00 s longer.

Now, the formula we need here is the one to calculate the distance traveled by a falling object. It goes like this:

d = (1/2) * g * t^2

where d is the distance, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time.

So, if the second stone has reached a speed of 12.0 m/s after 1.00 s, we can use this information to find the distance it traveled. We'll plug in the numbers and we have:

d = (1/2) * 9.8 m/s^2 * (1.00 s)^2

Calculating that gives us the distance that the second stone has traveled.

Now remember, the first stone has been falling for an additional 1.00 s, so to find the distance between them, we need to calculate how far it has fallen. We can use the same formula.

Therefore, the distance between the stones when the second one has reached a speed of 12.0 m/s would be the distance traveled by the first stone (after 2.00 s) minus the distance traveled by the second stone (after 1.00 s).

So, now it's time to do some math and find out how far apart these stones are!

To find the distance between the two stones when the second one has reached a speed of 12.0 m/s, you need to determine the time it took for the second stone to reach that speed and then calculate the distance traveled by each stone during that time.

1. First, we need to calculate the time it took for the second stone to reach a speed of 12.0 m/s. We know that the first stone was dropped from the roof of a high building, and the second stone was dropped 1.00s later. Therefore, the time for the second stone can be calculated as follows:

Time for second stone = Time for first stone + Time interval
= 0 + 1.00s
= 1.00s

2. With the time for the second stone being 1.00s, we can now calculate the distances traveled by each stone during this time.

Distance covered by the first stone = (1/2) * g * t^2 [where g is the acceleration due to gravity, and t is the time]
= (1/2) * 9.8 m/s^2 * (1.00s)^2
= 4.90 m

Distance covered by the second stone = (1/2) * g * t^2
= (1/2) * 9.8 m/s^2 * (1.00s)^2
= 4.90 m

3. Finally, to find the distance between the two stones, take the difference between the distances covered by each stone.

Distance between the stones = Distance covered by the second stone - Distance covered by the first stone
= 4.90 m - 4.90 m
= 0 m

Therefore, when the second stone reaches a speed of 12.0 m/s, the distance between the stones is 0 meters.

Hmmm, seem to have lost my name.