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A stone is dropped from the roof of a high building. A second stone is dropped 1.00s laterHow far apart are the stones when the second one has reached a speed of 12.0m/s ?

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2 answers

  1. v = Vi + 9.8 t
    12 = 0 + 9.8 t
    t = 1.22 seconds that the second stone is in the air so the first one is in the air for 2.22 seconds
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    First stone:
    d = (1/2) 9.8 (2.22)^2
    = 24.1 meters
    Second stone:
    d = (1/2) 9.8 (1.22)^2
    = 7.3 meters
    ---------------------------
    so
    24.1 - 7.3 = 16.8 meters difference

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  2. Hmmm, seem to have lost my name.

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