the molarity of 2% by weight of aqueous solution of H2S4(molecular weight = 98)

100%=98g/mol=1mol

2%=X mol
Therefore
X=(2×1)÷100
X=0.02

2% w/w means 2g H2SO4/100 g soln or 20g/1000g solution.

20g is how many mols? That's 20/molar mass = ?
M = mols/L solution. You don't know the volume of the solution. You need the density to determine that.
volume = mass/density converted to L. Then M = mols/L will give it to you

To find the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters). In this case, you have a 2% by weight aqueous solution of H2S4 with a molecular weight of 98.

1. Start by determining the mass of H2S4 in the solution:
- If you have 2% by weight solution, it means that there are 2 grams of H2S4 in 100 grams of solution.
- Therefore, the mass of H2S4 in the solution is (2/100) * weight of the solution.

2. Convert the mass of H2S4 to moles:
- To convert grams to moles, divide the mass by the molar mass.
- In this case, divide the mass of H2S4 by its molecular weight of 98.

3. Determine the volume of the solution:
- If the volume is not given, you will need to measure it.
- Make sure to measure it in liters.

4. Calculate the molarity of the solution:
- Molarity (M) is defined as moles of solute divided by liters of solution.
- Divide the moles of H2S4 calculated in step 2 by the volume of the solution in liters.

So, by following these steps, you can find the molarity of the 2% by weight aqueous solution of H2S4.

Thanks a lot

chemistry