the heat of vaporization for water is 540 cal/g. how many kilocalories are needed to change 22g of liquid water to steam at 100*c?
12
22 g x 540 cal/g = ? cal
Well, I guess you could say that turning water into steam requires some serious "heating up." Now, let's do the math.
Given that the heat of vaporization for water is 540 cal/g, we need to find out how many calories are needed to vaporize the 22g of liquid water.
So, let's calculate:
22g x 540 cal/g = 11,880 cal
But wait, we need the answer in kilocalories! Fear not, kilocalories and calories are just like cousins twice removed.
To convert calories to kilocalories, we divide by 1,000.
11,880 cal ÷ 1,000 = 11.88 kcal
So, you would need approximately 11.88 kilocalories to change 22g of liquid water to steam at 100°C. That's a whole lot of energy, but hey, turning water into steam isn't child's play!
To calculate the number of kilocalories needed to change 22g of liquid water to steam at 100°C, we need to use the heat of vaporization value.
Given:
Heat of vaporization of water = 540 cal/g
Mass of water = 22g
To convert from calories to kilocalories, we divide by 1000 because 1 kilocalorie = 1000 calories.
Step 1: Calculate the heat required to vaporize the given mass of water in calories.
Heat = Mass * Heat of vaporization
Heat = 22g * 540 cal/g
Step 2: Convert the heat from calories to kilocalories.
Heat = (22g * 540 cal/g) / 1000
Therefore, the number of kilocalories needed is:
Heat = 11.88 kcal
Hence, it takes approximately 11.88 kilocalories to change 22g of liquid water to steam at 100°C.
To find the number of kilocalories required to change 22g of liquid water to steam at 100°C, we can use the formula:
Q = m * H
Where:
Q = heat energy
m = mass of the substance
H = heat of vaporization
First, let's convert the heat of vaporization from calories to kilocalories. Since 1 kilocalorie (kcal) is equal to 1000 calories, we can divide the given heat of vaporization by 1000:
Heat of vaporization (H) = 540 cal/g / 1000 = 0.54 kcal/g
Now, we can calculate the heat energy required to change the 22g of water to steam:
Q = 22g * 0.54 kcal/g
Q = 11.88 kcal
Therefore, it would require 11.88 kilocalories to change 22g of liquid water to steam at 100°C.