write the net ionic equation for the unknown titration reaction in this experiment.
KHC8H4O4(aq) + NaOH(aq)----> KNaC8H4O4 + H2O(l)
Write the molecular equation. You have done that. Now change that into ions. I will leave the (aq) off each but you understand it is there.
Since KHC8H4O4 is (aq), then it will ionize:
K^+ + HC8H4O4^- + Na^+ OH^- ==> K^+ + Na^+ + C8H4O4^= + H2O
All I have done is to write those materials that are strong electrolytes (100% ionized) as ions and those that are weak elecrolytes (less than 100% ionized) as the molecule. Note that I made an error in the equation I first wrote and didn't catch it until I did the detail work here. So disregard the first response.
Now look to see which materials are common to both sides. K^+ is on both ies so cancel them. Na^+ is so cancel that. Nothing else is so here is what is left.
HC8H4O4^- + OH^- ==> C8H4O4^= + H2O
So what the ionic equation shows is that the hydrogen tartrate ion + the hydroxide ion from the base neutralize each other (H from the hydrogen tartrate ion going with OH from NaOH to form water. I'm glad I redid this or I would have given you the wrong answer.
H^+ + OH^- ==>H2O
The important questions is, "Do you understand why this is the net ionic equation?"
not exactly
Dude, That is a freakin HAAAAARRRDDD
guestion. your in colledge right??
Oh, titrations, the chemistry equivalent of a balancing act on a unicycle! Okay, let's clown around with the net ionic equation for this equation!
We can start by writing the complete equation:
KHC8H4O4(aq) + NaOH(aq) ----> KNaC8H4O4 + H2O(l)
To find the net ionic equation, we need to eliminate any spectator ions, those sneaky little molecules that just hang around without actually participating in the reaction. In this case, potassium (K+) and sodium (Na+) are both spectator ions because they appear on both sides of the equation.
So, let's kick those spectators out of the circus tent and focus on the actual reaction:
HC8H4O4(aq) + OH-(aq) ----> C8H4O4- + H2O(l)
And there you have it! The net ionic equation, where only the players on the stage are left. Clowns, I mean chemicals, coming together to create a new compound and water!
To write the net ionic equation for the unknown titration reaction, we need to first identify the spectator ions.
In the given reaction:
KHC8H4O4(aq) + NaOH(aq) --> KNaC8H4O4 + H2O(l)
The complete ionic equation of the reaction can be written as:
K+(aq) + HC8H4O4-(aq) + Na+(aq) + OH-(aq) --> K+(aq) + Na+(aq) + C8H4O4-(aq) + H2O(l)
Now, let's identify the spectator ions. Spectator ions are the ions that remain the same on both the reactant and product sides of the equation. In this case, the spectator ions are the K+ and Na+ ions since they are present on both sides of the equation.
Therefore, the net ionic equation will only include the species that are directly involved in the reaction. The net ionic equation is as follows:
HC8H4O4-(aq) + OH-(aq) --> C8H4O4-(aq) + H2O(l)
In this net ionic equation, the spectator ions (K+ and Na+) are removed, leaving behind only the ions involved in the chemical change during the titration.