# a)Calculate the mass percent of carbon in the hydrated form of the solid that has the formula BeC2O4 loosly bonded to 3H2O.

b)When heated to 220degrees C, BeC2O4loosly bonded to 3H2O(s) dehydrates completely as represented below:

BeC2O4loosely bonded to 3H2O ==> BeC2O4 + 3H2O

if 3.21g of BeC2O4loosely bonded to 3H2O is heated to 220 degrees C, calculate

the mass of BeC2O4 formed, and,

the volume of the H2O released, measured at 220 degrees C and 735mm Hg.

For a, there are two carbons for each molecule BeC2O4.3H2O

Percent C= 2*12/molmassBeC2O4.3H2O *100

For b.

Determine the percent of BeC2O4 in the hydrated form.

Percent BeC2O4 = molmassBeC2O4/molmassBeC2O4.3H2O *100

Then grams of BeC2O4 formed is the above percent x 1/100 * 3.21

then how do u find:

the volume of the H2O released, measured at 220 degrees C and 735mm Hg.

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