A myopic student is shaving without his glasses. If his eyes have a far point of 1.5, what is the greatest distance he can stand from the mirror and still see his image clearly?
i donr know
1.5
To determine the greatest distance the myopic student can stand from the mirror and still see his image clearly, we need to consider the far point of his eyes.
The far point is the maximum distance at which a myopic person can see objects clearly without using their glasses. In this case, the far point of the student's eyes is given as 1.5 meters.
To find the maximum distance he can stand from the mirror, we'll use the formula:
Maximum distance = Far point + Distance of the mirror
Let's assume the distance of the mirror to be 'd' meters.
Substituting the given values into the formula:
Maximum distance = 1.5 meters + d meters
To see his image clearly, the student's eyes should be able to focus at the virtual image formed by the mirror. This occurs when the image is at the far point of the student's eyes.
Therefore, the maximum distance the student can stand from the mirror and still see his image clearly is when the virtual image formed by the mirror is at his far point.
In this case, the maximum distance the student can stand from the mirror is 1.5 meters.
To answer this question, we need to understand the concept of near point and far point in relation to myopia, also known as nearsightedness.
The near point is the closest distance at which a person with myopia can see objects clearly. In this case, the near point is not given, but we can assume it to be around 25 cm, which is the near point for an average human eye.
The far point is the maximum distance at which a person with myopia can see objects clearly without using corrective lenses (such as glasses or contact lenses). In this case, the far point is given as 1.5 meters.
To determine the greatest distance the myopic student can stand from the mirror and still see his image clearly, we need to consider the following:
1. Myopic students can see objects clearly when they are closer to their eyes than the far point.
2. The distance from the student's eyes to the mirror should be greater than the near point to ensure clear vision.
Given that the myopic student's far point is 1.5 meters, we can assume that he can see objects clearly when they are placed around 1.5 meters or closer to his eyes.
To find the greatest distance he can stand from the mirror and still see his image clearly, we can use the following calculation:
Greatest distance = far point - near point
Greatest distance = 1.5 meters - 25 cm (which converts to 0.25 meters)
Greatest distance ≈ 1.25 meters
Therefore, the myopic student can stand at a maximum distance of approximately 1.25 meters from the mirror and still see his image clearly without his glasses.