A mixture of petrol and oil for a two stroke lawn mower contains 85% petrol, how much oil is required for 18 litres of the fuel mixture?
Well, if the mixture contains 85% petrol, then we can assume that the remaining 15% is oil. So, in 18 liters of the fuel mixture, you would need 15% of that for the oil.
To calculate how much oil is required, we can use a simple proportion.
If 15% is equal to the amount of oil needed, then we can set up the proportion like this:
(15 / 100) = x / 18
Now, cross-multiply and solve for x:
100x = 15 * 18
x = (15 * 18) / 100
x = 2.7 liters of oil
So, for 18 liters of the fuel mixture, you would need approximately 2.7 liters of oil. Now, please don't make a clown of yourself and add any funny business to your fuel mixture! Safety first, my friend!
To find out how much oil is required for 18 litres of the fuel mixture, we first need to calculate the amount of petrol in the mixture.
Given that the mixture contains 85% petrol, we can calculate the amount of petrol in the mixture by multiplying the total volume of the mixture by the percentage of petrol:
Petrol in mixture = 18 litres x 85% = 15.3 litres
Next, we can calculate the amount of oil required by subtracting the amount of petrol in the mixture from the total volume of the mixture:
Oil required = Total volume of mixture - Petrol in mixture
= 18 litres - 15.3 litres
= 2.7 litres
Therefore, for 18 litres of the fuel mixture, you would need 2.7 litres of oil.
To determine the amount of oil required for the fuel mixture, we'll need to use the given information that the mixture contains 85% petrol and 15% oil.
Step 1: Calculate the amount of petrol in 18 litres of the mixture:
Petrol = 85% × 18 litres
= (85/100) × 18 litres
= 0.85 × 18 litres
= 15.3 litres
Step 2: Calculate the amount of oil required:
Oil = 15% × 18 litres
= (15/100) × 18 litres
= 0.15 × 18 litres
= 2.7 litres
Therefore, for 18 litres of the fuel mixture, you would require 2.7 litres of oil.
18*.85 = 15.3 litres are petrol, so
2.7 litres are oil