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We have an important chemsitry test due and I want to make sure that I do not mess up on my algebra. I am dealing with the integrated rate law, but my question is purely algebraically in nature. I hope, somebody can help me.

1) ln(A) = -kt+ln(B)

solve for t
solve for k
solve for B

2) 1/(B) = kt + 1/(B)

solve for k
solve for t
solve for B

Thank you so much for your help. It is greatly appreciated

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5 answers
  1. 1)
    ln(A) = -kt+ln(B)
    kt = lnB - lnA
    kt = ln(B/A)
    t = ln(B/A) / k

    k = ln(B/A) / t

    lnB = lnA + kt
    B = e^(lnA + kt)

    2)
    1/B = kt + 1/B
    0 = kt
    t = 0
    or
    k = 0
    B is any value except B≠0
    (are you sure you have no typo in 2) ?

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  2. 2) should be 1/(B) = kt+1(A)
    I am dealing with concentrations and A and B are just placeholders for the concentrations.
    Thanks

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  3. 2) I thought there was something wrong with your first typing of the question

    1/B = kt + 1/A
    multiply each term by AB, the LCD
    A = ABkt + B
    A - B = ABkt
    t = (A-B)/(ABk)
    k = (A-b)/(ABt)

    from: A = ABkt + B
    A = B(Akt + 1)
    B = A/(Akt + 1)

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  4. kt00 b =2

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  5. Solve:
    3x(x + 4) + 3(x + 4) = 0
    A) 0 and -4
    B) -1 and 4
    C) -1 and -4
    D) 1 and 4

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