What is the molarity of a solution prepared by dissolving 5.86 grams of naoh in enough water to make 250 milliliters of solution
how many moles of NaOH is 5.86g?
multiply that by 4 to get the M.
(250ml = 1/4 liter)
0.586
To find the molarity (M) of a solution, you need to know the number of moles of solute (NaOH) and the volume of the solution in liters.
Step 1: Convert the mass of NaOH from grams to moles.
The molar mass of NaOH is 22.99 g/mol for Na, 15.99 g/mol for O, and 1.01 g/mol for H.
So, the molar mass of NaOH is 22.99 g/mol + 15.99 g/mol + 1.01 g/mol = 39.99 g/mol.
To find the number of moles, divide the mass of NaOH by its molar mass:
5.86 g NaOH / 39.99 g/mol = 0.1465 mol NaOH.
Step 2: Convert the volume of the solution from milliliters to liters.
The volume of the solution is given as 250 milliliters. To convert to liters, divide by 1000:
250 mL / 1000 = 0.250 L.
Step 3: Calculate the molarity (M) of the solution.
Molarity (M) is defined as moles of solute (NaOH) divided by liters of solution (volume):
M = moles of solute / liters of solution
M = 0.1465 mol NaOH / 0.250 L = 0.586 M.
Therefore, the molarity of the NaOH solution prepared by dissolving 5.86 grams in enough water to make 250 milliliters of solution is 0.586 M.