rewrite the expression by factoring out (v+5)
5v^2(v+5)+3(v+5)
2u^2 (u+5)+5 (u+5)
(5v^2)(v+5)+(3)(v+5)
(5v^2+3)(v+5)
5v^3+25v^2+3v+15
To rewrite the expression by factoring out (v+5), we can consider (v+5) as a common factor and apply the distributive property.
First, let's factor out (v+5) from both terms:
5v^2(v+5) + 3(v+5)
= (v+5)(5v^2) + (v+5)(3)
Now, we can distribute (v+5) to each term inside the parentheses:
= 5v^2(v) + 5v^2(5) + 3(v) + 3(5)
Simplifying each term:
= 5v^3 + 25v^2 + 3v + 15
Therefore, the expression after factoring out (v+5) is:
5v^3 + 25v^2 + 3v + 15