Which action(s) will decrease the equilibrium concentration of a non-reacting gas in water?
1. decreasing the temp. of the water
2. decreasing the volume of water
3. decreasing the pressure of the gas above the liquid
a. 1 only
b. 2 only
c. 3 only
d. 1 and 3
e. 1, 2, and 3
1. decreasing the T of the water usually allows more gas to dissolve.
2. decreasing the volume of water will decrease the amount of gas proportionally but the concn will stay the same.
3. decreasing the pressure of the gas above a liquid will decrease the concn of the gas in the liquid. Henry's Law.
so the answer is 3 only?
That's what I think.
To determine which action(s) will decrease the equilibrium concentration of a non-reacting gas in water, we need to consider the factors that influence the solubility of gases in water.
1. Decreasing the temperature of the water: According to Henry's Law, the solubility of a gas in a liquid decreases with increasing temperature. Therefore, decreasing the temperature of the water will decrease the equilibrium concentration of the gas in the water.
2. Decreasing the volume of water: The volume of water does not directly affect the solubility of a gas in water. Therefore, reducing the volume of water will not have any impact on the equilibrium concentration of the gas.
3. Decreasing the pressure of the gas above the liquid: According to Henry's Law, the solubility of a gas in a liquid is directly proportional to the pressure of the gas above the liquid. As the pressure decreases, the solubility decreases, and therefore, the equilibrium concentration of the gas in the water decreases.
Based on the explanations above, the correct answer is:
c. 3 only (decreasing the pressure of the gas above the liquid)