A flute can be regarded as a tube open at both ends. It will emit a musical note if the flutist excites a standing wave in the air column inside the tube.
The lowest musical note that can be played on a flute is C (261.7 Hz). What must be the length of the tube? Assume that the air column is vibrating in its fundamental mode.
ans: 0.657
some one plz help.....!
F = V/(2L) |=> L = V/(2*F), V - Sound speed in air
To determine the length of the tube required to produce the lowest musical note (C) on a flute, we can use the fundamental frequency formula for tubes open at both ends:
f = (v / 2L)
Where:
- f is the frequency of the standing wave (261.7 Hz for C)
- v is the speed of sound in air (approximately 343 m/s at room temperature)
- L is the length of the tube we want to find
Rearranging the formula to solve for L, we have:
L = v / (2f)
Substituting the given values, we get:
L = 343 m/s / (2 * 261.7 Hz)
Calculating this, we find:
L ≈ 0.655 meters or 65.5 cm
Therefore, the length of the tube should be approximately 0.655 meters or 65.5 centimeters to produce the lowest musical note (C) on a flute.