In the right triangle shown below, the length of AB is 8 units, ¡ÏA measures 60¡ã, sin 60¡ã ¡Ö 0.866,
cos 60¡ã ¡Ö 0.5, and tan 60¡ã ¡Ö 1.73. Approximately how many units long is BC , to the nearest
hundredth of a unit?
A. 4.00
Since you posted this twice, I think you realized that the symbols did not come out like you intended.
I think you meant this:
AB = 8, angle A = 60°
then you are given
sin60° = .866
cos60° = .5
tan60° = 1.73
the problem is that we don't know where the 90° angle is, could be at C or at B
If angle B = 90°
then
BC/8 = tan60
BC = 8tan60 = 8(1.732) = appr 13.86
if angle C = 90°
then
BC/8 = sin60
BC = 8sin60 = 8(.866) = appr 6.93
If it helps the answer according to this ACT compass sample test questions print out is 6.93.
How to solve it is the question ...
C is a 90 degree angle.
AB is 8 and the hypotenuse.
AC is the base .... we don't know it's length.
It's on page 14 if you google this -
2014 ACT In the right triangle shown below, the length of AB is 8 units
6.93
Oh, I see you're trying to trig me! Alright, let's do some math and have some fun at the same time!
Since we have a right triangle and we know the length of AB is 8 units, and we're looking for the length of BC, we can use sine to solve this.
We know that sin 60° is approximately 0.866, so we can set up an equation:
sin 60° = BC/AB
0.866 = BC/8
Now, let's solve for BC:
BC = 0.866 * 8
BC ≈ 6.928 units
So, to the nearest hundredth of a unit, BC is approximately 6.93 units long.
To find the length of BC in the right triangle, we can use the trigonometric function sine (sin).
In the given triangle, sin 60° is equal to the length of BC divided by the length of AB.
sin 60° = BC / AB
We can rearrange this equation to solve for BC.
BC = sin 60° * AB
Substituting the given values, we have:
BC = 0.866 * 8
Simplifying the expression, we get:
BC = 6.93
Therefore, BC is approximately 6.93 units long to the nearest hundredth.