A man travels 4km due north,then travels 6km due east and further travels 4km due north .how far he is from the starting point.

so now he's 8km N and 6km E

The distance is the hypotenuse, so he's 10km away.

A plane left a town and travelled 96km on the bearing of 045. Tt then went southwards until it was 96km from the starting point. How far southward did it to the nearest km?

To find the total distance the man is from the starting point, we can break down the movements into two steps:

Step 1: Northward movement - The man travels 4km due north, so he moves 4km directly upward.

Step 2: Eastward movement - After the first step, the man moves 6km due east, which is to the right.

Now, we can visualize these movements on a graph:

| North |
| ↑
| ↑ 4km
| ↑
| ↑
------------------ ← Starting point
6km → East


By connecting the ending point of the first step with the starting point of the second step, we form a right-angled triangle.

Using the Pythagorean theorem, we can find the distance (d) between the starting point and the ending point (total distance):

d = sqrt((4km)^2 + (6km)^2)

Solving this equation:

d = sqrt(16km^2 + 36km^2)
= sqrt(52km^2)
= 7.21km (rounded to two decimal places)

Therefore, the man is approximately 7.21km away from the starting point.

Solve it