Hydrogren, a possible future fuel, can also be obtained from other compounds such as ethanol. Ethanol can be made from the fermentation of crops, such as corn. How much hydrogen in grams can be obtained from 1.0 kg of ethanol (C2H5OH)?

132g H

To determine the amount of hydrogen that can be obtained from 1.0 kg of ethanol (C2H5OH), we need to consider the molar ratio between ethanol and hydrogen.

First, let's calculate the molar mass of ethanol (C2H5OH):
C = 12.01 g/mol
H = 1.008 g/mol (there are 6 hydrogen atoms in ethanol)
O = 16.00 g/mol

Molar mass of ethanol (C2H5OH) = (2 * C) + (6 * H) + O
= (2 * 12.01 g/mol) + (6 * 1.008 g/mol) + 16.00 g/mol
= 46.07 g/mol

Next, we need to determine the molar mass of hydrogen (H2):
H = 1.008 g/mol

Molar mass of hydrogen (H2) = 2 * H = 2 * 1.008 g/mol = 2.016 g/mol

Now, we can set up the molar ratio between ethanol and hydrogen:
Molar ratio: 1 mol C2H5OH : 3 mol H2

To calculate the moles of ethanol in 1.0 kg, we need to divide the mass of ethanol by its molar mass:
Moles of ethanol = (1.0 kg) / (46.07 g/mol)

Now, we can calculate the moles of hydrogen that can be obtained from the moles of ethanol:
Moles of H2 = Moles of ethanol * (3 mol H2 / 1 mol C2H5OH)

Finally, to calculate the mass of hydrogen, we multiply the moles of hydrogen by its molar mass:
Mass of H2 = Moles of H2 * (2.016 g/mol)

Substituting the values into the formulas, we get:
Moles of ethanol = (1000 g) / (46.07 g/mol) ≈ 21.69 mol
Moles of H2 = 21.69 mol * (3 mol H2 / 1 mol C2H5OH) ≈ 65.07 mol
Mass of H2 = 65.07 mol * (2.016 g/mol) ≈ 131.17 g

Therefore, approximately 131.17 grams of hydrogen can be obtained from 1.0 kg of ethanol (C2H5OH).

To determine the amount of hydrogen (H2) that can be obtained from 1.0 kg of ethanol (C2H5OH), we need to consider the molar ratio between the two compounds.

Let's start by calculating the molar mass of ethanol (C2H5OH):
C: 12.01 g/mol x 2 = 24.02 g/mol
H: 1.01 g/mol x 6 = 6.06 g/mol
O: 16.00 g/mol x 1 = 16.00 g/mol
Total molar mass: 46.08 g/mol

Next, we can determine the molar ratio of hydrogen atoms in ethanol. From the molecular formula of ethanol (C2H5OH), we can see that there are 6 hydrogen atoms (H).

Molar ratio:
6 moles of H / 1 mole of C2H5OH

Now we need to convert the mass of ethanol to moles. To do this, we'll divide the mass of ethanol by its molar mass:
1.0 kg = 1000 g
Number of moles of ethanol:
1000 g / 46.08 g/mol ≈ 21.67 moles

Finally, we can calculate the amount of hydrogen in grams by multiplying the number of moles of ethanol by the molar ratio of hydrogen atoms:
21.67 moles of C2H5OH x (6 moles of H / 1 mole of C2H5OH) x (1.01 g/mol of H) ≈ 130.20 g

Therefore, approximately 130.20 grams of hydrogen can be obtained from 1.0 kg of ethanol (C2H5OH).

2CH3CH2OH + 2Na �¨ 2CH3CH2ONa + H2

so if it is obtained from the reaction with a metal then.

1.0kg((1000g/kg)(1mol ethanol/46.06844g)(1mol H2/2mol ethanol)(2.01588g/mol H2)=________g H