Graph the quadratic functions
y = -2x^2 and y = -2x^2 + 4
on a separate piece of paper. Using those graphs, compare and contrast the shape and position of the graphs
Not even having graphed this, I can tell that the second graph is simply the first one moved upwards 4 units
Try it, it is really simple.
Just find some ordered pairs for each and join them with a smooth line.
(You should get two parabolas, both opening downwards, do one at a time)
You guys does any one hav the answers for Lesson 4: Graphs and Proportional Relationships CE 2015
Math 7 B Unit 4: Graphing in the Coordinate Plane please
Just noticed that Henry did this same question.
Compare your point that you found with his
http://www.jiskha.com/display.cgi?id=1364257845
Yass
To graph the quadratic functions y = -2x^2 and y = -2x^2 + 4, we can start by plotting a few points and then connecting them to form a curve.
Function y = -2x^2:
Let's substitute various values of x into the equation and calculate the corresponding y-values:
When x = -2, y = -2 * (-2)^2 = -8
When x = -1, y = -2 * (-1)^2 = -2
When x = 0, y = -2 * (0)^2 = 0
When x = 1, y = -2 * (1)^2 = -2
When x = 2, y = -2 * (2)^2 = -8
Graphing these points, we have the following curve:
(-2,-8) (-1,-2) (0,0) (1,-2) (2,-8)
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From this graph, we can see that the curve opens downwards, forming a "U" shape. Its vertex is at point (0,0).
Function y = -2x^2 + 4:
Let's calculate the y-values for different x-values:
When x = -2, y = -2 * (-2)^2 + 4 = 8
When x = -1, y = -2 * (-1)^2 + 4 = 2
When x = 0, y = -2 * (0)^2 + 4 = 4
When x = 1, y = -2 * (1)^2 + 4 = 2
When x = 2, y = -2 * (2)^2 + 4 = 8
Graphing these points, we have the following curve:
(-2,8) (-1,2) (0,4) (1,2) (2,8)
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Comparing the two curves, we can see that both are quadratic functions with the same coefficient -2 in front of x^2. The only difference is the constant term. The graph of y = -2x^2 + 4 is the same as y = -2x^2 shifted upward by 4 units.
Therefore, both curves have the same shape, which is a downward-opening "U," but they have different positions. The graph of y = -2x^2 is centered at the origin (0,0), while the graph of y = -2x^2 + 4 is shifted upward by 4 units.
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