the width of a rectangle is 3 less than twice the length of x. if area of rectangle is 43 in sq ft. which equation can be used to find length in feet
a. 2x(x-3)=43
b.2x+2(2x-3)=43
c.x(3-2x)=43
d.x(2x-3)=43
i think its d
:) thank you
length ---- x
"width is 3 less than twice x" ---- 2x - 3
so what do you think ?
Well, I would hope you would pick that one.
I think its d
To find the equation that can be used to find the length of the rectangle, let's break down the given information and use it to derive the equation.
1. The width of the rectangle is 3 less than twice the length of x:
Width = 2x - 3
2. The area of the rectangle is given as 43 square feet:
Area = length × width = 43
Now, let's substitute the expressions we have for width and area into the equation:
Length × Width = Area
Length × (2x - 3) = 43
Simplifying this equation, we get:
2xLength - 3Length = 43
So, the correct equation that can be used to find the length of the rectangle is:
d. x(2x - 3) = 43