How do I solve this exponent problem? I understand the exponent rules, but I getting 1 but 1 is not the answer! I don't want anyone to solve the problem for me, I want to learn how to solve this type of problem. Thank you!

Solve the equation:

-8=-3-6 (3sqrtx^2)

Thanks again!

-3 -6(3*sqrtx^2) = -8.

1. Isolate the term with the radical by
adding 3 to both sides.

2. Divide both sides by -6 and get:
3x = 5/6.

3. Divide both sides by 3 and get:
X = 5/18.

3.

To solve the equation -8 = -3 - 6 (3√x^2), we can follow these steps:

Step 1: Simplify the equation as much as possible.

Start by simplifying the expression on the right side of the equation. Since we have an exponent of 2 inside a square root, we can simplify it using the exponent rule for radicals.

Recall that for any real number a, (a^n)^m = a^(n * m).

In this case, we have (3√x^2)^2. When we square the expression inside the radical, the radical disappears, and we are left with x^2.

So, our equation simplifies to: -8 = -3 - 6x^2

Step 2: Move all terms to one side of the equation.

To solve the equation, we want to isolate the variable x. So, we should move all terms to one side of the equation, typically the left side.

-8 + 3 + 6x^2 = 0

-5 + 6x^2 = 0

Step 3: Solve for x by factoring or using the quadratic formula.

In this case, we have a quadratic equation in the form of Ax^2 + Bx + C = 0, with A = 6, B = 0, and C = -5.

Since B is zero, the quadratic equation can be factored as:

(√A * x)^2 - (√C)^2 = 0

This simplifies to:

(√6x)^2 - (√-5)^2 = 0

6x - 5 = 0

Step 4: Solve for x.

Now, solve the equation 6x - 5 = 0 for x.

Add 5 to both sides:

6x = 5

Divide both sides by 6:

x = 5/6

So, the solution to the equation -8 = -3 - 6(3√x^2) is x = 5/6.

Remember that it's important to always double-check your answers by substituting the value back into the original equation to confirm its validity.