A man has a rectangular garden. One length of the garden lies along a patio wall. However the rest of the garden is enclosed by 32 feet of fencing. If the length of the garden is twice its width, what is the area of the garden.
w+w+2w=32
w=8
the garden is 8x16 so the area is 128ft^2
To find the area of the garden, we need to determine the length and width of the garden first.
Let's say the width of the garden is x feet. Since the length of the garden is twice its width, the length would be 2x feet.
Now, we know that one length of the garden lies along a patio wall, which means that the perimeter of the garden is the sum of the two lengths and the two widths.
The perimeter is given as 32 feet, so we can set up the equation:
2x + 2(2x) = 32
Solving this equation will give us the value of x, which represents the width of the garden. Let's solve it:
2x + 4x = 32
6x = 32
x = 32/6
x = 5.33 feet (rounded to the nearest hundredth)
Now that we have the width, we can find the length by multiplying it by 2:
Length = 2 * 5.33 = 10.66 feet (rounded to the nearest hundredth)
The area of a rectangle is calculated by multiplying the length and width, so the area of the garden is:
Area = Length * Width
Area = 10.66 * 5.33
Area ≈ 56.8 square feet (rounded to the nearest tenth)
Therefore, the approximate area of the garden is 56.8 square feet.
If you don't know what your School Subject is, who does? I suspect it's math.
P = 2L + 2W
32 = L + 2(0.5L)
32 = 2L
16 = L
Its not a school subject. its college
And Ms.sue. Your wrong. Cause if the length is 16 then the width is 8 and that will equal 24. Nice try
Ms Sue is right. 16+8+8=32
There are two widths
I'm so sorry, Lee, that you don't realize that college is a school. At least most colleges are schools for educating students. What is the name of your college?
A fence needs to go around the entire garden. It has two lengths and two widths, right? One length lies along the wall. That means that two widths and one length are enclosed by the fence.
16 + 8 + 8 = 32